Magnetism And Matter Class 12 Physics Revision — Grandmaster Guide
Ayush (Founder)
Exam Strategist
- B = μ₀nI
- F = IL × B
- F = qv × B
- τ = nIAB
- μ = μ₀ × (n × I × A)
- M = nIA
- B = μ₀H + μ₀M
- χ = (μ - 1)
- μ = (1 + χ)
- B = μ₀(H + M)
- Magnetic field on axis of loop = μ₀I/(2r)
- Magnetic field on perpendicular bisector of loop = μ₀I/(2πr³)³
- Magnetic field due to solenoid = μ₀nI
- Magnetic field due to toroid = μ₀nI/(2πr)
- Force per unit length = μ₀I₁I₂/(2πr)
🪤 The 5 Mistakes That Cost Marks
- Not using the correct formula for magnetic field due to a current carrying wire
- Forgetting to consider the direction of magnetic field while calculating force on a current carrying wire
- Not understanding the concept of magnetic moment and its relation to magnetic field
- Incorrectly applying the formula for magnetic field due to a solenoid
- Not considering the effect of magnetic field on a moving charge
✏️ 3 Solved PYQs
- A current of 10 A is flowing ∈ a wire of length 1 m. The wire is placed ∈ a magnetic field of 0.1 T. If the angle between the wire and magnetic field is 30°, calculate the force acting on the wire.
- F = IL × B = 10 × 1 × 0.1 × s∈(30°) = 0.5 N
- A solenoid of length 10 cm and radius 1 cm has 1000 turns. If a current of 5 A is flowing through it, calculate the magnetic field at its center.
- B = μ₀nI = 4π × 10⁻⁷ × 1000 × 5 = 0.0628 T
- A bar magnet of magnetic moment 10 A m² is placed ∈ a magnetic field of 0.1 T. If the angle between the magnet and magnetic field is 60°, calculate the torque acting on the magnet.
- τ = MB s∈(θ) = 10 × 0.1 × s∈(60°) = 0.866 Nm
🧠 The One Thing Most Students Get Wrong
- The concept of magnetic moment and its relation to magnetic field. Many students get confused between the two and end up using the wrong formula.
👁️ Ayush's Note
- To solve problems related to magnetism, always start by identifying the given quantities and the unknown quantity.
- Use the formula bank to find the relevant formula for the problem.
- Always consider the direction of magnetic field and the angle between the wire and magnetic field while calculating force.
- Practice problems regularly to develop a strong understanding of the concepts.
🔁 Last 5 Minutes Box
- Revise the formula for magnetic field due to a current carrying wire.
- Go through the concept of magnetic moment and its relation to magnetic field.
- Practice a few problems related to force on a current carrying wire and magnetic field due to a solenoid.
- Make sure to understand the concept of torque and its relation to magnetic moment.
📝 Practice MCQs
1. What is the magnetic field at the center of a solenoid of length 10 cm and radius 1 cm with 1000 turns, if a current of 5 A is flowing through it?
A) 0.01 T
B) 0.0628 T
C) 0.1 T
D) 1 T
Answer: B) 0.0628 T. Explanation: B = μ₀nI = 4π × 10⁻⁷ × 1000 × 5 = 0.0628 T
2. A current of 10 A is flowing ∈ a wire of length 1 m. The wire is placed ∈ a magnetic field of 0.1 T. If the angle between the wire and magnetic field is 30°, what is the force acting on the wire?
A) 0.1 N
B) 0.5 N
C) 1 N
D) 5 N
Answer: B) 0.5 N. Explanation: F = IL × B = 10 × 1 × 0.1 × s∈(30°) = 0.5 N
3. A bar magnet of magnetic moment 10 A m² is placed ∈ a magnetic field of 0.1 T. If the angle between the magnet and magnetic field is 60°, what is the torque acting on the magnet?
A) 0.5 Nm
B) 0.866 Nm
C) 1 Nm
D) 5 Nm
Answer: B) 0.866 Nm. Explanation: τ = MB s∈(θ) = 10 × 0.1 × s∈(60°) = 0.866 Nm
4. What is the magnetic field due to a current carrying loop of radius 1 m and current 5 A at a point on its axis at a distance of 2 m from its center?
A) 0.01 T
B) 0.0628 T
C) 0.1 T
D) 1 T
Answer: A) 0.01 T. Explanation: B = μ₀I/(2r) = 4π × 10⁻⁷ × 5/(2 × 2) = 0.01 T
5. A toroid of radius 10 cm and 1000 turns is carrying a current of 5 A. What is the magnetic field at its center?
A) 0.01 T
B) 0.0628 T
C) 0.1 T
D) 1 T
Answer: B) 0.0628 T. Explanation: B = μ₀nI/(2πr) = 4π × 10⁻⁷ × 1000 × 5/(2π × 0.1) = 0.0628 T
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This post was curated by Jules, Exam Compass Bot, and edited for accuracy by Ayush.
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