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Communication Systems Class 12 Physics Revision β€” Grandmaster Guide

A

Ayush (Founder)

Exam Strategist

Last Updated: 2026-04-20
  • E = hf, where E is energy, h is Planck's constant, and f is frequency
  • Ξ» = c/f, where Ξ» is wavelength, c is speed of light, and f is frequency
  • c = 1/√(ΞΌβ‚€Ξ΅β‚€), where c is speed of light, ΞΌβ‚€ is permeability of free space, and Ξ΅β‚€ is permittivity of free space
  • P = E/T, where P is power, E is energy, and T is time
  • i = Q/t, where i is current, Q is charge, and t is time
  • R = ρ(l/A), where R is resistance, ρ is resistivity, l is length, and A is area
  • Xβ‚— = 2Ο€fL, where Xβ‚— is inductive reactance, f is frequency, and L is inductance
  • Xβ‚— = Ο‰L, where Xβ‚— is inductive reactance, Ο‰ is angular frequency, and L is inductance
  • Xβ‚— = 2Ο€fL, where Xβ‚— is inductive reactance, f is frequency, and L is inductance
  • Xβ‚œ = 1/(Ο‰C), where Xβ‚œ is capacitive reactance, Ο‰ is angular frequency, and C is capacitance
  • Z = √(RΒ² + (Xβ‚— - Xβ‚œ)Β²), where Z is impedance, R is resistance, Xβ‚— is inductive reactance, and Xβ‚œ is capacitive reactance
  • P = VΒ²/R, where P is power, V is voltage, and R is resistance

πŸͺ€ The 5 Mistakes That Cost Marks

  • Not understanding the concept of signal modulation and demodulation
  • Confusing amplitude modulation (AM) and frequency modulation (FM)
  • Not knowing the difference between analog and digital communication systems
  • Forgetting the formula for signal-to-noise ratio (SNR) and its importance ∈ communication systems
  • Not being able to apply the concept of bandwidth and its relation to data transfer rate

✏️ 3 Solved PYQs

  • Question 1: A message signal of frequency 10 kHz is used to modulate a carrier wave of frequency 1 MHz. What is the frequency of the upper sideband?
  • Step 1: Identify the frequency of the message signal (10 kHz) and the carrier wave (1 MHz)
  • Step 2: Calculate the frequency of the upper sideband using the formula fβ‚˜ + fβ‚—, where fβ‚˜ is the frequency of the message signal and fβ‚— is the frequency of the carrier wave
  • Step 3: Substitute the values and calculate the frequency of the upper sideband (1 MHz + 10 kHz = 1.01 MHz)
  • Answer: 1.01 MHz
  • Question 2: A signal is transmitted through a communication system with a bandwidth of 100 kHz. If the signal-to-noise ratio (SNR) is 10, what is the data transfer rate?
  • Step 1: Identify the bandwidth (100 kHz) and SNR (10)
  • Step 2: Calculate the data transfer rate using the formula R = B logβ‚‚(1 + SNR), where R is the data transfer rate, B is the bandwidth, and SNR is the signal-to-noise ratio
  • Step 3: Substitute the values and calculate the data transfer rate (100 kHz logβ‚‚(1 + 10) = 665.74 kbps)
  • Answer: 665.74 kbps
  • Question 3: A digital signal is transmitted through a communication system with a data transfer rate of 1 Mbps. If the signal is sampled at a rate of 2 MHz, what is the number of bits per sample?
  • Step 1: Identify the data transfer rate (1 Mbps) and the sampling rate (2 MHz)
  • Step 2: Calculate the number of bits per sample using the formula n = R/fβ‚›, where n is the number of bits per sample, R is the data transfer rate, and fβ‚› is the sampling rate
  • Step 3: Substitute the values and calculate the number of bits per sample (1 Mbps / 2 MHz = 0.5 bits per sample)
  • Answer: 0.5 bits per sample

🧠 The One Thing Most Students Get Wrong

  • Most students get confused between the concepts of amplitude modulation (AM) and frequency modulation (FM). They often forget that ∈ AM, the amplitude of the carrier wave is varied ∈ accordance with the message signal, while ∈ FM, the frequency of the carrier wave is varied.

πŸ‘οΈ Ayush's Note

  • To solve problems related to communication systems, it is essential to understand the concepts of signal modulation and demodulation, and the difference between analog and digital communication systems.
  • Practice problems related to signal-to-noise ratio (SNR) and data transfer rate to improve your understanding of these concepts.
  • Make sure to remember the formulas related to communication systems, such as the formula for signal-to-noise ratio (SNR) and the formula for data transfer rate.

πŸ” Last 5 Minutes Box

  • Revision of key concepts: signal modulation and demodulation, amplitude modulation (AM) and frequency modulation (FM), signal-to-noise ratio (SNR), and data transfer rate
  • Practice of formulas: f = 1/T, Ξ» = c/f, E = hf, P = VΒ²/R, and R = ρ(l/A)
  • Quick review of solved problems and practice questions to reinforce understanding of concepts

πŸ“ Practice MCQs

1. What is the purpose of modulation ∈ a communication system?

A) To increase the frequency of the signal

B) To decrease the amplitude of the signal

C) To vary the characteristics of the carrier wave ∈ accordance with the message signal

D) To reduce the bandwidth of the signal

Answer: C) To vary the characteristics of the carrier wave ∈ accordance with the message signal

2. Which of the following is a type of analog modulation?

A) Pulse code modulation (PCM)

B) Amplitude shift keying (ASK)

C) Frequency shift keying (FSK)

D) Amplitude modulation (AM)

Answer: D) Amplitude modulation (AM)

3. What is the signal-to-noise ratio (SNR) of a communication system with a signal power of 100 W and a noise power of 10 W?

A) 10

B) 20

C) 30

D) 40

Answer: A) 10

4. A signal is transmitted through a communication system with a bandwidth of 100 kHz. If the signal-to-noise ratio (SNR) is 10, what is the data transfer rate?

A) 100 kbps

B) 500 kbps

C) 665.74 kbps

D) 1 Mbps

Answer: C) 665.74 kbps

5. A digital signal is transmitted through a communication system with a data transfer rate of 1 Mbps. If the signal is sampled at a rate of 2 MHz, what is the number of bits per sample?

A) 0.25 bits per sample

B) 0.5 bits per sample

C) 1 bit per sample

D) 2 bits per sample

Answer: B) 0.5 bits per sample


πŸš€ Ready to Ace Your Exam?

Put your knowledge to the test! Take the free Practice Mock Test now and track your progress against thousands of students.

πŸ“š Academic References

Content verified against peer-reviewed research:

  1. Smart Substation Communications and Cybersecurity: A Comprehensiv... β€” IEEE Communications Surveys & Tutorials (2023) πŸ”“ β€” DOI β†—
  2. El Agente: An autonomous agent for quantum chemistry β€” Matter (2025) πŸ”“ β€” DOI β†—
  3. The Era of Digital Transition in the Prism of the Existential Thr... β€” Sustainability (2024) πŸ”“ β€” DOI β†—

πŸ”“ = Open Access article

🎬 Watch video explanations on YouTube β†’


This post was curated by Jules, Exam Compass Bot, and edited for accuracy by Ayush.


πŸ“š Related Topics

Continue your revision with these related guides:

  • πŸ“– Operating Systems Class 12 Exam Prep Revision β€” Grandmaster Guide
  • πŸ“– Number Systems 9 Class 9 Exam Prep Revision β€” Grandmaster Guide
  • πŸ“– Atoms Class 12 Physics Revision β€” Grandmaster Guide
  • πŸ“– Electromagnetic Waves Class 12 Physics Revision β€” Grandmaster Guide
A

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JEE Aspirant & Founder β€” KV Darbhanga

I'm a JEE Aspirant building Exam Compass to solve the "Black Box" problem of exam preparation. Every featureβ€”from the Neural Mock Engine to the Cognitive Decay Mapsβ€”exists because I needed a way to verify my readiness with mathematical certainty. This isn't just a platform; it's the infrastructure I built to win, and now it's open to every student in the trenches.

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Empowering Students with AI-Driven Engineering.
Prepared for Scholar
Date: 2026-04-20
CATEGORY: Exam Notes
  • E = hf, where E is energy, h is Planck's constant, and f is frequency
  • Ξ» = c/f, where Ξ» is wavelength, c is speed of light, and f is frequency
  • c = 1/√(ΞΌβ‚€Ξ΅β‚€), where c is speed of light, ΞΌβ‚€ is permeability of free space, and Ξ΅β‚€ is permittivity of free space
  • P = E/T, where P is power, E is energy, and T is time
  • i = Q/t, where i is current, Q is charge, and t is time
  • R = ρ(l/A), where R is resistance, ρ is resistivity, l is length, and A is area
  • Xβ‚— = 2Ο€fL, where Xβ‚— is inductive reactance, f is frequency, and L is inductance
  • Xβ‚— = Ο‰L, where Xβ‚— is inductive reactance, Ο‰ is angular frequency, and L is inductance
  • Xβ‚— = 2Ο€fL, where Xβ‚— is inductive reactance, f is frequency, and L is inductance
  • Xβ‚œ = 1/(Ο‰C), where Xβ‚œ is capacitive reactance, Ο‰ is angular frequency, and C is capacitance
  • Z = √(RΒ² + (Xβ‚— - Xβ‚œ)Β²), where Z is impedance, R is resistance, Xβ‚— is inductive reactance, and Xβ‚œ is capacitive reactance
  • P = VΒ²/R, where P is power, V is voltage, and R is resistance

πŸͺ€ The 5 Mistakes That Cost Marks

  • Not understanding the concept of signal modulation and demodulation
  • Confusing amplitude modulation (AM) and frequency modulation (FM)
  • Not knowing the difference between analog and digital communication systems
  • Forgetting the formula for signal-to-noise ratio (SNR) and its importance ∈ communication systems
  • Not being able to apply the concept of bandwidth and its relation to data transfer rate

✏️ 3 Solved PYQs

  • Question 1: A message signal of frequency 10 kHz is used to modulate a carrier wave of frequency 1 MHz. What is the frequency of the upper sideband?
  • Step 1: Identify the frequency of the message signal (10 kHz) and the carrier wave (1 MHz)
  • Step 2: Calculate the frequency of the upper sideband using the formula fβ‚˜ + fβ‚—, where fβ‚˜ is the frequency of the message signal and fβ‚— is the frequency of the carrier wave
  • Step 3: Substitute the values and calculate the frequency of the upper sideband (1 MHz + 10 kHz = 1.01 MHz)
  • Answer: 1.01 MHz
  • Question 2: A signal is transmitted through a communication system with a bandwidth of 100 kHz. If the signal-to-noise ratio (SNR) is 10, what is the data transfer rate?
  • Step 1: Identify the bandwidth (100 kHz) and SNR (10)
  • Step 2: Calculate the data transfer rate using the formula R = B logβ‚‚(1 + SNR), where R is the data transfer rate, B is the bandwidth, and SNR is the signal-to-noise ratio
  • Step 3: Substitute the values and calculate the data transfer rate (100 kHz logβ‚‚(1 + 10) = 665.74 kbps)
  • Answer: 665.74 kbps
  • Question 3: A digital signal is transmitted through a communication system with a data transfer rate of 1 Mbps. If the signal is sampled at a rate of 2 MHz, what is the number of bits per sample?
  • Step 1: Identify the data transfer rate (1 Mbps) and the sampling rate (2 MHz)
  • Step 2: Calculate the number of bits per sample using the formula n = R/fβ‚›, where n is the number of bits per sample, R is the data transfer rate, and fβ‚› is the sampling rate
  • Step 3: Substitute the values and calculate the number of bits per sample (1 Mbps / 2 MHz = 0.5 bits per sample)
  • Answer: 0.5 bits per sample

🧠 The One Thing Most Students Get Wrong

  • Most students get confused between the concepts of amplitude modulation (AM) and frequency modulation (FM). They often forget that ∈ AM, the amplitude of the carrier wave is varied ∈ accordance with the message signal, while ∈ FM, the frequency of the carrier wave is varied.

πŸ‘οΈ Ayush's Note

  • To solve problems related to communication systems, it is essential to understand the concepts of signal modulation and demodulation, and the difference between analog and digital communication systems.
  • Practice problems related to signal-to-noise ratio (SNR) and data transfer rate to improve your understanding of these concepts.
  • Make sure to remember the formulas related to communication systems, such as the formula for signal-to-noise ratio (SNR) and the formula for data transfer rate.

πŸ” Last 5 Minutes Box

  • Revision of key concepts: signal modulation and demodulation, amplitude modulation (AM) and frequency modulation (FM), signal-to-noise ratio (SNR), and data transfer rate
  • Practice of formulas: f = 1/T, Ξ» = c/f, E = hf, P = VΒ²/R, and R = ρ(l/A)
  • Quick review of solved problems and practice questions to reinforce understanding of concepts

πŸ“ Practice MCQs

1. What is the purpose of modulation ∈ a communication system?

A) To increase the frequency of the signal

B) To decrease the amplitude of the signal

C) To vary the characteristics of the carrier wave ∈ accordance with the message signal

D) To reduce the bandwidth of the signal

Answer: C) To vary the characteristics of the carrier wave ∈ accordance with the message signal

2. Which of the following is a type of analog modulation?

A) Pulse code modulation (PCM)

B) Amplitude shift keying (ASK)

C) Frequency shift keying (FSK)

D) Amplitude modulation (AM)

Answer: D) Amplitude modulation (AM)

3. What is the signal-to-noise ratio (SNR) of a communication system with a signal power of 100 W and a noise power of 10 W?

A) 10

B) 20

C) 30

D) 40

Answer: A) 10

4. A signal is transmitted through a communication system with a bandwidth of 100 kHz. If the signal-to-noise ratio (SNR) is 10, what is the data transfer rate?

A) 100 kbps

B) 500 kbps

C) 665.74 kbps

D) 1 Mbps

Answer: C) 665.74 kbps

5. A digital signal is transmitted through a communication system with a data transfer rate of 1 Mbps. If the signal is sampled at a rate of 2 MHz, what is the number of bits per sample?

A) 0.25 bits per sample

B) 0.5 bits per sample

C) 1 bit per sample

D) 2 bits per sample

Answer: B) 0.5 bits per sample


πŸš€ Ready to Ace Your Exam?

Put your knowledge to the test! Take the free Practice Mock Test now and track your progress against thousands of students.

πŸ“š Academic References

Content verified against peer-reviewed research:

  1. Smart Substation Communications and Cybersecurity: A Comprehensiv... β€” IEEE Communications Surveys & Tutorials (2023) πŸ”“ β€” DOI β†—
  2. El Agente: An autonomous agent for quantum chemistry β€” Matter (2025) πŸ”“ β€” DOI β†—
  3. The Era of Digital Transition in the Prism of the Existential Thr... β€” Sustainability (2024) πŸ”“ β€” DOI β†—

πŸ”“ = Open Access article

🎬 Watch video explanations on YouTube β†’


This post was curated by Jules, Exam Compass Bot, and edited for accuracy by Ayush.


πŸ“š Related Topics

Continue your revision with these related guides:

  • πŸ“– Operating Systems Class 12 Exam Prep Revision β€” Grandmaster Guide
  • πŸ“– Number Systems 9 Class 9 Exam Prep Revision β€” Grandmaster Guide
  • πŸ“– Atoms Class 12 Physics Revision β€” Grandmaster Guide
  • πŸ“– Electromagnetic Waves Class 12 Physics Revision β€” Grandmaster Guide