Top 50 Most Repeated WAVES PYQs | JEE MAINS
A curated collection of the most important questions from WAVES, fully solved with step-by-step concepts to prepare for JEE MAINS.
A curated collection of the most important questions from WAVES, fully solved with step-by-step concepts to prepare for JEE MAINS.
Use Doppler formula: $f' = f \frac{v}{v - v_s} = 600 \times \frac{330}{300} = 660\,\text{Hz}$....
Read Full Step-by-Step Solution →Beat frequency is absolute difference: $|260 - 256| = 4\,\text{Hz}$....
Read Full Step-by-Step Solution →Constructive interference occurs when phase difference is 0, 2π, 4π,... radians....
Read Full Step-by-Step Solution →For a pipe open at both ends, the fundamental wavelength is $\lambda = 2L$. Hence $f = v/\lambda = v/(2L) = 340/(2\times1.2) \approx 141.7\ \text{Hz}$...
Read Full Step-by-Step Solution →Since $v \propto \sqrt{T}$ for a given gas, the ratio of the new speed to the original speed is $\sqrt{600/300}=\sqrt{2}$. Hence the speed of sound in...
Read Full Step-by-Step Solution →The wave speed is $v = \frac{\omega}{k}$ with $\omega = 2\pi\,$rad/s and $k = \pi\,$rad/m, giving $v = 2\,$m/s....
Read Full Step-by-Step Solution →From $k = 4\pi$, $\omega = 8\pi$, $v = \omega/k = 2\,\text{m/s}$....
Read Full Step-by-Step Solution →The general form of a wave is $ y = A \sin(\omega t - kx) $. Comparing, $ \omega = 4\pi $, $ k = 2\pi $. Wave speed $ v = \frac{\omega}{k} = \frac{4\p...
Read Full Step-by-Step Solution →For a string fixed at both ends, the wavelength for the $ n^{\text{th}} $ harmonic is $ \lambda_n = \frac{2L}{n} $. For the third harmonic ($ n=3 $), ...
Read Full Step-by-Step Solution →$v \propto \sqrt{T}$, $T_1 = 273$, $T_2 = 373$, so $v_2 = 332 \times \sqrt{373/273} \approx 387$ m/s....
Read Full Step-by-Step Solution →The wave number is given by $k = 2\pi/\lambda$. Substituting $\lambda = 0.5\ \text{m}$ gives $k = 4\pi\ \text{rad\,m}^{-1}$....
Read Full Step-by-Step Solution →From $v = \sqrt{\gamma R T/M}$, $v$ is directly proportional to $\sqrt{T}$ and $\sqrt{\gamma}$, and inversely proportional to $\sqrt{M}$. Hence raisin...
Read Full Step-by-Step Solution →Beat frequency = |f1 - f2|. So, 256 - f2 = 4 → f2 = 252 Hz....
Read Full Step-by-Step Solution →For a string fixed at both ends, the wavelength of the $n$-th harmonic is $\lambda_n = \frac{2L}{n}$. For third harmonic ($n=3$), $\lambda = \frac{2L}...
Read Full Step-by-Step Solution →Use Doppler formula: $f' = f \frac{v}{v - v_s} = 600 \times \frac{330}{300} = 660\,\text{Hz}$....
Read Full Step-by-Step Solution →Beat frequency is absolute difference: $|260 - 256| = 4\,\text{Hz}$....
Read Full Step-by-Step Solution →Constructive interference occurs when phase difference is 0, 2π, 4π,... radians....
Read Full Step-by-Step Solution →For a pipe open at both ends, the fundamental wavelength is $\lambda = 2L$. Hence $f = v/\lambda = v/(2L) = 340/(2\times1.2) \approx 141.7\ \text{Hz}$...
Read Full Step-by-Step Solution →Since $v \propto \sqrt{T}$ for a given gas, the ratio of the new speed to the original speed is $\sqrt{600/300}=\sqrt{2}$. Hence the speed of sound in...
Read Full Step-by-Step Solution →The wave speed is $v = \frac{\omega}{k}$ with $\omega = 2\pi\,$rad/s and $k = \pi\,$rad/m, giving $v = 2\,$m/s....
Read Full Step-by-Step Solution →From $k = 4\pi$, $\omega = 8\pi$, $v = \omega/k = 2\,\text{m/s}$....
Read Full Step-by-Step Solution →The general form of a wave is $ y = A \sin(\omega t - kx) $. Comparing, $ \omega = 4\pi $, $ k = 2\pi $. Wave speed $ v = \frac{\omega}{k} = \frac{4\p...
Read Full Step-by-Step Solution →For a string fixed at both ends, the wavelength for the $ n^{\text{th}} $ harmonic is $ \lambda_n = \frac{2L}{n} $. For the third harmonic ($ n=3 $), ...
Read Full Step-by-Step Solution →$v \propto \sqrt{T}$, $T_1 = 273$, $T_2 = 373$, so $v_2 = 332 \times \sqrt{373/273} \approx 387$ m/s....
Read Full Step-by-Step Solution →The wave number is given by $k = 2\pi/\lambda$. Substituting $\lambda = 0.5\ \text{m}$ gives $k = 4\pi\ \text{rad\,m}^{-1}$....
Read Full Step-by-Step Solution →From $v = \sqrt{\gamma R T/M}$, $v$ is directly proportional to $\sqrt{T}$ and $\sqrt{\gamma}$, and inversely proportional to $\sqrt{M}$. Hence raisin...
Read Full Step-by-Step Solution →Beat frequency = |f1 - f2|. So, 256 - f2 = 4 → f2 = 252 Hz....
Read Full Step-by-Step Solution →For a string fixed at both ends, the wavelength of the $n$-th harmonic is $\lambda_n = \frac{2L}{n}$. For third harmonic ($n=3$), $\lambda = \frac{2L}...
Read Full Step-by-Step Solution →Use Doppler formula: $f' = f \frac{v}{v - v_s} = 600 \times \frac{330}{300} = 660\,\text{Hz}$....
Read Full Step-by-Step Solution →Beat frequency is absolute difference: $|260 - 256| = 4\,\text{Hz}$....
Read Full Step-by-Step Solution →Constructive interference occurs when phase difference is 0, 2π, 4π,... radians....
Read Full Step-by-Step Solution →For a pipe open at both ends, the fundamental wavelength is $\lambda = 2L$. Hence $f = v/\lambda = v/(2L) = 340/(2\times1.2) \approx 141.7\ \text{Hz}$...
Read Full Step-by-Step Solution →Since $v \propto \sqrt{T}$ for a given gas, the ratio of the new speed to the original speed is $\sqrt{600/300}=\sqrt{2}$. Hence the speed of sound in...
Read Full Step-by-Step Solution →The wave speed is $v = \frac{\omega}{k}$ with $\omega = 2\pi\,$rad/s and $k = \pi\,$rad/m, giving $v = 2\,$m/s....
Read Full Step-by-Step Solution →From $k = 4\pi$, $\omega = 8\pi$, $v = \omega/k = 2\,\text{m/s}$....
Read Full Step-by-Step Solution →The general form of a wave is $ y = A \sin(\omega t - kx) $. Comparing, $ \omega = 4\pi $, $ k = 2\pi $. Wave speed $ v = \frac{\omega}{k} = \frac{4\p...
Read Full Step-by-Step Solution →For a string fixed at both ends, the wavelength for the $ n^{\text{th}} $ harmonic is $ \lambda_n = \frac{2L}{n} $. For the third harmonic ($ n=3 $), ...
Read Full Step-by-Step Solution →$v \propto \sqrt{T}$, $T_1 = 273$, $T_2 = 373$, so $v_2 = 332 \times \sqrt{373/273} \approx 387$ m/s....
Read Full Step-by-Step Solution →The wave number is given by $k = 2\pi/\lambda$. Substituting $\lambda = 0.5\ \text{m}$ gives $k = 4\pi\ \text{rad\,m}^{-1}$....
Read Full Step-by-Step Solution →From $v = \sqrt{\gamma R T/M}$, $v$ is directly proportional to $\sqrt{T}$ and $\sqrt{\gamma}$, and inversely proportional to $\sqrt{M}$. Hence raisin...
Read Full Step-by-Step Solution →Beat frequency = |f1 - f2|. So, 256 - f2 = 4 → f2 = 252 Hz....
Read Full Step-by-Step Solution →For a string fixed at both ends, the wavelength of the $n$-th harmonic is $\lambda_n = \frac{2L}{n}$. For third harmonic ($n=3$), $\lambda = \frac{2L}...
Read Full Step-by-Step Solution →