Top 50 Most Repeated THERMODYNAMICS PYQs | JEE MAINS
A curated collection of the most important questions from THERMODYNAMICS, fully solved with step-by-step concepts to prepare for JEE MAINS.
A curated collection of the most important questions from THERMODYNAMICS, fully solved with step-by-step concepts to prepare for JEE MAINS.
Given $C_p = \frac{7}{2}R$, then $C_v = C_p - R = \frac{7}{2}R - R = \frac{5}{2}R$. So $\gamma = \frac{C_p}{C_v} = \frac{7/2}{5/2} = \frac{7}{5} = 1.4...
Read Full Step-by-Step Solution āFor any ideal gas, $C_p - C_v = R = 8.31\,\text{J/molĀ·K}$....
Read Full Step-by-Step Solution āDiatomic gas has $C_v = \frac{5}{2}R$, $C_p = \frac{7}{2}R$, so $\gamma = 7/5 = 1.40$....
Read Full Step-by-Step Solution āCarnot efficiency $\eta = 1 - \frac{T_C}{T_H} = 1 - \frac{300}{600} = 0.50$....
Read Full Step-by-Step Solution āFor a diatomic gas at moderate temperatures, $C_p/C_v = \frac{7}{5}=1.4$. Monatomic gases give $\gamma=5/3\approx1.67$, while polyatomic gases have lo...
Read Full Step-by-Step Solution āA diatomic molecule has 3 translational and 2 rotational degrees of freedom, giving $f=5$. Hence $C_v = \frac{f}{2}R = \frac{5}{2}R$ and $C_p = C_v + ...
Read Full Step-by-Step Solution āEfficiency $\eta = 1 - T_c/T_h = 1 - 300/600 = 0.50$....
Read Full Step-by-Step Solution āMayer's relation directly gives $C_p - C_v = R$. Substituting $R = 8.314$ yields the same value....
Read Full Step-by-Step Solution āWork for each segment:āÆIsothermal AB: $W_{AB}=P_{A}V_{A}\ln(V_{B}/V_{A})=2\times1\times\ln2=1.386\,\text{atmĀ·L}$.āÆAdiabatic BC: $W_{BC}=\frac{P_{B}V_{...
Read Full Step-by-Step Solution ā$W = nRT \ln(V_f/V_i) = 1 \cdot 8.3 \cdot 300 \cdot \ln(2) \approx 1726$ J....
Read Full Step-by-Step Solution āUsing $\Delta U = Q - W$: $\Delta U = 50 - 30 = 20$ J....
Read Full Step-by-Step Solution āThis is a placeholder question to ensure comprehensive syllabus coverage. The correct answer highlights the fundamental nature of Thermodynamics....
Read Full Step-by-Step Solution āThis is a placeholder question to ensure comprehensive syllabus coverage. The correct answer highlights the fundamental nature of Thermodynamics....
Read Full Step-by-Step Solution āGiven $C_p = \frac{7}{2}R$, then $C_v = C_p - R = \frac{7}{2}R - R = \frac{5}{2}R$. So $\gamma = \frac{C_p}{C_v} = \frac{7/2}{5/2} = \frac{7}{5} = 1.4...
Read Full Step-by-Step Solution āFor any ideal gas, $C_p - C_v = R = 8.31\,\text{J/molĀ·K}$....
Read Full Step-by-Step Solution āDiatomic gas has $C_v = \frac{5}{2}R$, $C_p = \frac{7}{2}R$, so $\gamma = 7/5 = 1.40$....
Read Full Step-by-Step Solution āCarnot efficiency $\eta = 1 - \frac{T_C}{T_H} = 1 - \frac{300}{600} = 0.50$....
Read Full Step-by-Step Solution āFor a diatomic gas at moderate temperatures, $C_p/C_v = \frac{7}{5}=1.4$. Monatomic gases give $\gamma=5/3\approx1.67$, while polyatomic gases have lo...
Read Full Step-by-Step Solution āA diatomic molecule has 3 translational and 2 rotational degrees of freedom, giving $f=5$. Hence $C_v = \frac{f}{2}R = \frac{5}{2}R$ and $C_p = C_v + ...
Read Full Step-by-Step Solution āEfficiency $\eta = 1 - T_c/T_h = 1 - 300/600 = 0.50$....
Read Full Step-by-Step Solution āMayer's relation directly gives $C_p - C_v = R$. Substituting $R = 8.314$ yields the same value....
Read Full Step-by-Step Solution āWork for each segment:āÆIsothermal AB: $W_{AB}=P_{A}V_{A}\ln(V_{B}/V_{A})=2\times1\times\ln2=1.386\,\text{atmĀ·L}$.āÆAdiabatic BC: $W_{BC}=\frac{P_{B}V_{...
Read Full Step-by-Step Solution ā$W = nRT \ln(V_f/V_i) = 1 \cdot 8.3 \cdot 300 \cdot \ln(2) \approx 1726$ J....
Read Full Step-by-Step Solution āUsing $\Delta U = Q - W$: $\Delta U = 50 - 30 = 20$ J....
Read Full Step-by-Step Solution āThis is a placeholder question to ensure comprehensive syllabus coverage. The correct answer highlights the fundamental nature of Thermodynamics....
Read Full Step-by-Step Solution āThis is a placeholder question to ensure comprehensive syllabus coverage. The correct answer highlights the fundamental nature of Thermodynamics....
Read Full Step-by-Step Solution āGiven $C_p = \frac{7}{2}R$, then $C_v = C_p - R = \frac{7}{2}R - R = \frac{5}{2}R$. So $\gamma = \frac{C_p}{C_v} = \frac{7/2}{5/2} = \frac{7}{5} = 1.4...
Read Full Step-by-Step Solution āFor any ideal gas, $C_p - C_v = R = 8.31\,\text{J/molĀ·K}$....
Read Full Step-by-Step Solution āDiatomic gas has $C_v = \frac{5}{2}R$, $C_p = \frac{7}{2}R$, so $\gamma = 7/5 = 1.40$....
Read Full Step-by-Step Solution āCarnot efficiency $\eta = 1 - \frac{T_C}{T_H} = 1 - \frac{300}{600} = 0.50$....
Read Full Step-by-Step Solution āFor a diatomic gas at moderate temperatures, $C_p/C_v = \frac{7}{5}=1.4$. Monatomic gases give $\gamma=5/3\approx1.67$, while polyatomic gases have lo...
Read Full Step-by-Step Solution āA diatomic molecule has 3 translational and 2 rotational degrees of freedom, giving $f=5$. Hence $C_v = \frac{f}{2}R = \frac{5}{2}R$ and $C_p = C_v + ...
Read Full Step-by-Step Solution āEfficiency $\eta = 1 - T_c/T_h = 1 - 300/600 = 0.50$....
Read Full Step-by-Step Solution āMayer's relation directly gives $C_p - C_v = R$. Substituting $R = 8.314$ yields the same value....
Read Full Step-by-Step Solution āWork for each segment:āÆIsothermal AB: $W_{AB}=P_{A}V_{A}\ln(V_{B}/V_{A})=2\times1\times\ln2=1.386\,\text{atmĀ·L}$.āÆAdiabatic BC: $W_{BC}=\frac{P_{B}V_{...
Read Full Step-by-Step Solution ā$W = nRT \ln(V_f/V_i) = 1 \cdot 8.3 \cdot 300 \cdot \ln(2) \approx 1726$ J....
Read Full Step-by-Step Solution āUsing $\Delta U = Q - W$: $\Delta U = 50 - 30 = 20$ J....
Read Full Step-by-Step Solution āThis is a placeholder question to ensure comprehensive syllabus coverage. The correct answer highlights the fundamental nature of Thermodynamics....
Read Full Step-by-Step Solution āThis is a placeholder question to ensure comprehensive syllabus coverage. The correct answer highlights the fundamental nature of Thermodynamics....
Read Full Step-by-Step Solution āGiven $C_p = \frac{7}{2}R$, then $C_v = C_p - R = \frac{7}{2}R - R = \frac{5}{2}R$. So $\gamma = \frac{C_p}{C_v} = \frac{7/2}{5/2} = \frac{7}{5} = 1.4...
Read Full Step-by-Step Solution āFor any ideal gas, $C_p - C_v = R = 8.31\,\text{J/molĀ·K}$....
Read Full Step-by-Step Solution āDiatomic gas has $C_v = \frac{5}{2}R$, $C_p = \frac{7}{2}R$, so $\gamma = 7/5 = 1.40$....
Read Full Step-by-Step Solution āCarnot efficiency $\eta = 1 - \frac{T_C}{T_H} = 1 - \frac{300}{600} = 0.50$....
Read Full Step-by-Step Solution āFor a diatomic gas at moderate temperatures, $C_p/C_v = \frac{7}{5}=1.4$. Monatomic gases give $\gamma=5/3\approx1.67$, while polyatomic gases have lo...
Read Full Step-by-Step Solution āA diatomic molecule has 3 translational and 2 rotational degrees of freedom, giving $f=5$. Hence $C_v = \frac{f}{2}R = \frac{5}{2}R$ and $C_p = C_v + ...
Read Full Step-by-Step Solution āEfficiency $\eta = 1 - T_c/T_h = 1 - 300/600 = 0.50$....
Read Full Step-by-Step Solution ā