Top 50 Most Repeated VECTOR ALGEBRA PYQs | JEE MAINS
A curated collection of the most important questions from VECTOR ALGEBRA, fully solved with step-by-step concepts to prepare for JEE MAINS.
A curated collection of the most important questions from VECTOR ALGEBRA, fully solved with step-by-step concepts to prepare for JEE MAINS.
The area equals the magnitude of the cross product $|\mathbf{a}\times\mathbf{b}|$. Computing $\mathbf{a}\times\mathbf{b}= -\hat{i}-5\hat{j}-7\hat{k}$,...
Read Full Step-by-Step Solution →Vectors are perpendicular, so magnitude is $\sqrt{3^2+4^2}=5$....
Read Full Step-by-Step Solution →Cross product magnitude equals area of parallelogram formed by vectors....
Read Full Step-by-Step Solution →Coplanar vectors have scalar triple product zero. Solve $[\vec{a}\ \vec{b}\ \vec{c}] = 0$ to get $\lambda + \mu = 5$....
Read Full Step-by-Step Solution →Compute $\vec{A}\cdot\vec{B}=3\times5+4\times(-1)=11$. Magnitudes: $|\vec{A}|=5$, $|\vec{B}|=\sqrt{26}\approx5.099$. Then $\cos\theta=\frac{11}{5\time...
Read Full Step-by-Step Solution →Standard vector form: point + scalar × direction vector....
Read Full Step-by-Step Solution →Volume = absolute value of scalar triple product....
Read Full Step-by-Step Solution →Line: $\vec{r} = \vec{a} + \lambda\vec{b}$; use given point and direction vector....
Read Full Step-by-Step Solution →The area equals the magnitude of the cross product $|\mathbf{a}\times\mathbf{b}|$. Computing $\mathbf{a}\times\mathbf{b}= -\hat{i}-5\hat{j}-7\hat{k}$,...
Read Full Step-by-Step Solution →Vectors are perpendicular, so magnitude is $\sqrt{3^2+4^2}=5$....
Read Full Step-by-Step Solution →Cross product magnitude equals area of parallelogram formed by vectors....
Read Full Step-by-Step Solution →Coplanar vectors have scalar triple product zero. Solve $[\vec{a}\ \vec{b}\ \vec{c}] = 0$ to get $\lambda + \mu = 5$....
Read Full Step-by-Step Solution →Compute $\vec{A}\cdot\vec{B}=3\times5+4\times(-1)=11$. Magnitudes: $|\vec{A}|=5$, $|\vec{B}|=\sqrt{26}\approx5.099$. Then $\cos\theta=\frac{11}{5\time...
Read Full Step-by-Step Solution →Standard vector form: point + scalar × direction vector....
Read Full Step-by-Step Solution →Volume = absolute value of scalar triple product....
Read Full Step-by-Step Solution →Line: $\vec{r} = \vec{a} + \lambda\vec{b}$; use given point and direction vector....
Read Full Step-by-Step Solution →The area equals the magnitude of the cross product $|\mathbf{a}\times\mathbf{b}|$. Computing $\mathbf{a}\times\mathbf{b}= -\hat{i}-5\hat{j}-7\hat{k}$,...
Read Full Step-by-Step Solution →Vectors are perpendicular, so magnitude is $\sqrt{3^2+4^2}=5$....
Read Full Step-by-Step Solution →Cross product magnitude equals area of parallelogram formed by vectors....
Read Full Step-by-Step Solution →Coplanar vectors have scalar triple product zero. Solve $[\vec{a}\ \vec{b}\ \vec{c}] = 0$ to get $\lambda + \mu = 5$....
Read Full Step-by-Step Solution →Compute $\vec{A}\cdot\vec{B}=3\times5+4\times(-1)=11$. Magnitudes: $|\vec{A}|=5$, $|\vec{B}|=\sqrt{26}\approx5.099$. Then $\cos\theta=\frac{11}{5\time...
Read Full Step-by-Step Solution →Standard vector form: point + scalar × direction vector....
Read Full Step-by-Step Solution →Volume = absolute value of scalar triple product....
Read Full Step-by-Step Solution →Line: $\vec{r} = \vec{a} + \lambda\vec{b}$; use given point and direction vector....
Read Full Step-by-Step Solution →The area equals the magnitude of the cross product $|\mathbf{a}\times\mathbf{b}|$. Computing $\mathbf{a}\times\mathbf{b}= -\hat{i}-5\hat{j}-7\hat{k}$,...
Read Full Step-by-Step Solution →Vectors are perpendicular, so magnitude is $\sqrt{3^2+4^2}=5$....
Read Full Step-by-Step Solution →Cross product magnitude equals area of parallelogram formed by vectors....
Read Full Step-by-Step Solution →Coplanar vectors have scalar triple product zero. Solve $[\vec{a}\ \vec{b}\ \vec{c}] = 0$ to get $\lambda + \mu = 5$....
Read Full Step-by-Step Solution →Compute $\vec{A}\cdot\vec{B}=3\times5+4\times(-1)=11$. Magnitudes: $|\vec{A}|=5$, $|\vec{B}|=\sqrt{26}\approx5.099$. Then $\cos\theta=\frac{11}{5\time...
Read Full Step-by-Step Solution →Standard vector form: point + scalar × direction vector....
Read Full Step-by-Step Solution →Volume = absolute value of scalar triple product....
Read Full Step-by-Step Solution →Line: $\vec{r} = \vec{a} + \lambda\vec{b}$; use given point and direction vector....
Read Full Step-by-Step Solution →The area equals the magnitude of the cross product $|\mathbf{a}\times\mathbf{b}|$. Computing $\mathbf{a}\times\mathbf{b}= -\hat{i}-5\hat{j}-7\hat{k}$,...
Read Full Step-by-Step Solution →Vectors are perpendicular, so magnitude is $\sqrt{3^2+4^2}=5$....
Read Full Step-by-Step Solution →Cross product magnitude equals area of parallelogram formed by vectors....
Read Full Step-by-Step Solution →Coplanar vectors have scalar triple product zero. Solve $[\vec{a}\ \vec{b}\ \vec{c}] = 0$ to get $\lambda + \mu = 5$....
Read Full Step-by-Step Solution →Compute $\vec{A}\cdot\vec{B}=3\times5+4\times(-1)=11$. Magnitudes: $|\vec{A}|=5$, $|\vec{B}|=\sqrt{26}\approx5.099$. Then $\cos\theta=\frac{11}{5\time...
Read Full Step-by-Step Solution →Standard vector form: point + scalar × direction vector....
Read Full Step-by-Step Solution →Volume = absolute value of scalar triple product....
Read Full Step-by-Step Solution →Line: $\vec{r} = \vec{a} + \lambda\vec{b}$; use given point and direction vector....
Read Full Step-by-Step Solution →The area equals the magnitude of the cross product $|\mathbf{a}\times\mathbf{b}|$. Computing $\mathbf{a}\times\mathbf{b}= -\hat{i}-5\hat{j}-7\hat{k}$,...
Read Full Step-by-Step Solution →Vectors are perpendicular, so magnitude is $\sqrt{3^2+4^2}=5$....
Read Full Step-by-Step Solution →Cross product magnitude equals area of parallelogram formed by vectors....
Read Full Step-by-Step Solution →Coplanar vectors have scalar triple product zero. Solve $[\vec{a}\ \vec{b}\ \vec{c}] = 0$ to get $\lambda + \mu = 5$....
Read Full Step-by-Step Solution →