Top 50 Most Repeated SETS PYQs | JEE MAINS
A curated collection of the most important questions from SETS, fully solved with step-by-step concepts to prepare for JEE MAINS.
A curated collection of the most important questions from SETS, fully solved with step-by-step concepts to prepare for JEE MAINS.
$A \cup B = \{1,2,3,4,5,6\}$, $C^c = \{1,2,3,6\}$, intersection is $\{1,2,3,6\} \cap \{1,2,3,6\}$...
Read Full Step-by-Step Solution →Use $n(M \cup S) = 60 - 10 = 50$, then $n(M \cap S) = 35 + 28 - 50 = 13$....
Read Full Step-by-Step Solution →Cartesian product $A \times B \times A$ consists of ordered triples $(x, y, z)$ where $x \in A$, $y \in B$, $z \in A$. $|A| = 2$, $|B| = 2$. Total ele...
Read Full Step-by-Step Solution →$A \cup B = \{1,2,3\}$, so complement in $U$ is $\{4,5\}$....
Read Full Step-by-Step Solution →De Morgan's law states $(A \cup B)' = A' \cap B'$....
Read Full Step-by-Step Solution →The Cartesian product $ A \times B $ consists of all ordered pairs where the first element is from A and the second from B. So valid elements are (1,a...
Read Full Step-by-Step Solution →By De Morgan's law, the complement of a union equals the intersection of the complements: $(A\cup B)' = A'\cap B'$....
Read Full Step-by-Step Solution →Given $A \cup B = A \cup C$ and $A \cap B = A \cap C$, we use set algebra to deduce $B = C$. Consider elements in $B$ not in $A$: they must appear in ...
Read Full Step-by-Step Solution →Foundational check for Sets in Class 11. Study the core principles carefully for competitive exams....
Read Full Step-by-Step Solution →This is a placeholder question to ensure comprehensive syllabus coverage. The correct answer highlights the fundamental nature of Sets....
Read Full Step-by-Step Solution →$A \cup B = \{1,2,3,4,5,6\}$, $C^c = \{1,2,3,6\}$, intersection is $\{1,2,3,6\} \cap \{1,2,3,6\}$...
Read Full Step-by-Step Solution →Use $n(M \cup S) = 60 - 10 = 50$, then $n(M \cap S) = 35 + 28 - 50 = 13$....
Read Full Step-by-Step Solution →Cartesian product $A \times B \times A$ consists of ordered triples $(x, y, z)$ where $x \in A$, $y \in B$, $z \in A$. $|A| = 2$, $|B| = 2$. Total ele...
Read Full Step-by-Step Solution →$A \cup B = \{1,2,3\}$, so complement in $U$ is $\{4,5\}$....
Read Full Step-by-Step Solution →De Morgan's law states $(A \cup B)' = A' \cap B'$....
Read Full Step-by-Step Solution →The Cartesian product $ A \times B $ consists of all ordered pairs where the first element is from A and the second from B. So valid elements are (1,a...
Read Full Step-by-Step Solution →By De Morgan's law, the complement of a union equals the intersection of the complements: $(A\cup B)' = A'\cap B'$....
Read Full Step-by-Step Solution →Given $A \cup B = A \cup C$ and $A \cap B = A \cap C$, we use set algebra to deduce $B = C$. Consider elements in $B$ not in $A$: they must appear in ...
Read Full Step-by-Step Solution →Foundational check for Sets in Class 11. Study the core principles carefully for competitive exams....
Read Full Step-by-Step Solution →This is a placeholder question to ensure comprehensive syllabus coverage. The correct answer highlights the fundamental nature of Sets....
Read Full Step-by-Step Solution →$A \cup B = \{1,2,3,4,5,6\}$, $C^c = \{1,2,3,6\}$, intersection is $\{1,2,3,6\} \cap \{1,2,3,6\}$...
Read Full Step-by-Step Solution →Use $n(M \cup S) = 60 - 10 = 50$, then $n(M \cap S) = 35 + 28 - 50 = 13$....
Read Full Step-by-Step Solution →Cartesian product $A \times B \times A$ consists of ordered triples $(x, y, z)$ where $x \in A$, $y \in B$, $z \in A$. $|A| = 2$, $|B| = 2$. Total ele...
Read Full Step-by-Step Solution →$A \cup B = \{1,2,3\}$, so complement in $U$ is $\{4,5\}$....
Read Full Step-by-Step Solution →De Morgan's law states $(A \cup B)' = A' \cap B'$....
Read Full Step-by-Step Solution →The Cartesian product $ A \times B $ consists of all ordered pairs where the first element is from A and the second from B. So valid elements are (1,a...
Read Full Step-by-Step Solution →By De Morgan's law, the complement of a union equals the intersection of the complements: $(A\cup B)' = A'\cap B'$....
Read Full Step-by-Step Solution →Given $A \cup B = A \cup C$ and $A \cap B = A \cap C$, we use set algebra to deduce $B = C$. Consider elements in $B$ not in $A$: they must appear in ...
Read Full Step-by-Step Solution →Foundational check for Sets in Class 11. Study the core principles carefully for competitive exams....
Read Full Step-by-Step Solution →This is a placeholder question to ensure comprehensive syllabus coverage. The correct answer highlights the fundamental nature of Sets....
Read Full Step-by-Step Solution →$A \cup B = \{1,2,3,4,5,6\}$, $C^c = \{1,2,3,6\}$, intersection is $\{1,2,3,6\} \cap \{1,2,3,6\}$...
Read Full Step-by-Step Solution →Use $n(M \cup S) = 60 - 10 = 50$, then $n(M \cap S) = 35 + 28 - 50 = 13$....
Read Full Step-by-Step Solution →Cartesian product $A \times B \times A$ consists of ordered triples $(x, y, z)$ where $x \in A$, $y \in B$, $z \in A$. $|A| = 2$, $|B| = 2$. Total ele...
Read Full Step-by-Step Solution →$A \cup B = \{1,2,3\}$, so complement in $U$ is $\{4,5\}$....
Read Full Step-by-Step Solution →De Morgan's law states $(A \cup B)' = A' \cap B'$....
Read Full Step-by-Step Solution →The Cartesian product $ A \times B $ consists of all ordered pairs where the first element is from A and the second from B. So valid elements are (1,a...
Read Full Step-by-Step Solution →By De Morgan's law, the complement of a union equals the intersection of the complements: $(A\cup B)' = A'\cap B'$....
Read Full Step-by-Step Solution →Given $A \cup B = A \cup C$ and $A \cap B = A \cap C$, we use set algebra to deduce $B = C$. Consider elements in $B$ not in $A$: they must appear in ...
Read Full Step-by-Step Solution →Foundational check for Sets in Class 11. Study the core principles carefully for competitive exams....
Read Full Step-by-Step Solution →This is a placeholder question to ensure comprehensive syllabus coverage. The correct answer highlights the fundamental nature of Sets....
Read Full Step-by-Step Solution →$A \cup B = \{1,2,3,4,5,6\}$, $C^c = \{1,2,3,6\}$, intersection is $\{1,2,3,6\} \cap \{1,2,3,6\}$...
Read Full Step-by-Step Solution →Use $n(M \cup S) = 60 - 10 = 50$, then $n(M \cap S) = 35 + 28 - 50 = 13$....
Read Full Step-by-Step Solution →