Top 50 Most Repeated D AND F BLOCK ELEMENTS PYQs | JEE MAINS
A curated collection of the most important questions from D AND F BLOCK ELEMENTS, fully solved with step-by-step concepts to prepare for JEE MAINS.
A curated collection of the most important questions from D AND F BLOCK ELEMENTS, fully solved with step-by-step concepts to prepare for JEE MAINS.
Lanthanides fill the 4f subshell one electron at a time from La to Lu, leading to the lanthanide contraction. Their most stable oxidation state is +3;...
Read Full Step-by-Step Solution →Manganese, a d‑block element, can show +2, +4 and +7 oxidation states. In the +2 state (3d⁵) all five d‑electrons are unpaired, giving a magnetic mome...
Read Full Step-by-Step Solution →$ 2MnO_2 + 4KOH + O_2 \rightarrow 2K_2MnO_4 + 2H_2O $: 4 mol KOH per 2 mol $ MnO_2 $ → 2:1 ratio....
Read Full Step-by-Step Solution →Interstitial compounds are formed when small atoms like H, C, or N occupy interstitial sites in transition metal lattices. These compounds retain the ...
Read Full Step-by-Step Solution →$\text{Mn}^{2+}$ has electronic configuration $[Ar]\,3d^5$, all 5 electrons unpaired....
Read Full Step-by-Step Solution →$ Cr_2O_7^{2-} $ oxidizes $ Fe^{2+} $ to $ Fe^{3+} $ in acid medium....
Read Full Step-by-Step Solution →Fe²⁺ has unpaired electrons (paramagnetic) and exhibits +2, +3, +6 states....
Read Full Step-by-Step Solution →Gd-157 has high neutron absorption, used in therapy and reactors....
Read Full Step-by-Step Solution →They provide intermediate reaction paths using variable oxidation states....
Read Full Step-by-Step Solution →Acidified potassium dichromate oxidizes primary alcohols to aldehydes and then carboxylic acids. Ethanol is a primary alcohol. Others are not oxidizab...
Read Full Step-by-Step Solution →In an interstitial alloy, small atoms (like carbon) occupy the interstitial spaces of a metal lattice. Stainless steel contains carbon atoms in the ir...
Read Full Step-by-Step Solution →Assign oxidation numbers: In KMnO₄, K = +1, O = –2 (4 × –2 = –8). Let Mn = x. Then +1 + x – 8 = 0 ⇒ x = +7. In K₂Cr₂O₇, K = +1 (2 × +1 = +2), O = –2 (...
Read Full Step-by-Step Solution →In interstitial alloys, small atoms such as C or N occupy the interstitial spaces of the metal lattice, strengthening the metallic bonds. This results...
Read Full Step-by-Step Solution →Potassium permanganate is prepared from pyrolusite (MnO₂) via a series of steps. First, MnO₂ is fused with KOH in air to form K₂MnO₄. Then, K₂MnO₄ is ...
Read Full Step-by-Step Solution →Ethanol oxidation by acidified $\mathrm{K_2Cr_2O_7}$ requires only 1 dichromate ion for 3 ethanol molecules. The correct stoichiometry is $\mathrm{3C_...
Read Full Step-by-Step Solution →The substrate is a primary alcohol. Under acidic dichromate conditions it first forms the aldehyde, which is further oxidised to the corresponding car...
Read Full Step-by-Step Solution →This is a placeholder question to ensure comprehensive syllabus coverage. The correct answer highlights the fundamental nature of D and F Block Elemen...
Read Full Step-by-Step Solution →Lanthanides fill the 4f subshell one electron at a time from La to Lu, leading to the lanthanide contraction. Their most stable oxidation state is +3;...
Read Full Step-by-Step Solution →Manganese, a d‑block element, can show +2, +4 and +7 oxidation states. In the +2 state (3d⁵) all five d‑electrons are unpaired, giving a magnetic mome...
Read Full Step-by-Step Solution →$ 2MnO_2 + 4KOH + O_2 \rightarrow 2K_2MnO_4 + 2H_2O $: 4 mol KOH per 2 mol $ MnO_2 $ → 2:1 ratio....
Read Full Step-by-Step Solution →Interstitial compounds are formed when small atoms like H, C, or N occupy interstitial sites in transition metal lattices. These compounds retain the ...
Read Full Step-by-Step Solution →$\text{Mn}^{2+}$ has electronic configuration $[Ar]\,3d^5$, all 5 electrons unpaired....
Read Full Step-by-Step Solution →$ Cr_2O_7^{2-} $ oxidizes $ Fe^{2+} $ to $ Fe^{3+} $ in acid medium....
Read Full Step-by-Step Solution →Fe²⁺ has unpaired electrons (paramagnetic) and exhibits +2, +3, +6 states....
Read Full Step-by-Step Solution →Gd-157 has high neutron absorption, used in therapy and reactors....
Read Full Step-by-Step Solution →They provide intermediate reaction paths using variable oxidation states....
Read Full Step-by-Step Solution →Acidified potassium dichromate oxidizes primary alcohols to aldehydes and then carboxylic acids. Ethanol is a primary alcohol. Others are not oxidizab...
Read Full Step-by-Step Solution →In an interstitial alloy, small atoms (like carbon) occupy the interstitial spaces of a metal lattice. Stainless steel contains carbon atoms in the ir...
Read Full Step-by-Step Solution →Assign oxidation numbers: In KMnO₄, K = +1, O = –2 (4 × –2 = –8). Let Mn = x. Then +1 + x – 8 = 0 ⇒ x = +7. In K₂Cr₂O₇, K = +1 (2 × +1 = +2), O = –2 (...
Read Full Step-by-Step Solution →In interstitial alloys, small atoms such as C or N occupy the interstitial spaces of the metal lattice, strengthening the metallic bonds. This results...
Read Full Step-by-Step Solution →Potassium permanganate is prepared from pyrolusite (MnO₂) via a series of steps. First, MnO₂ is fused with KOH in air to form K₂MnO₄. Then, K₂MnO₄ is ...
Read Full Step-by-Step Solution →Ethanol oxidation by acidified $\mathrm{K_2Cr_2O_7}$ requires only 1 dichromate ion for 3 ethanol molecules. The correct stoichiometry is $\mathrm{3C_...
Read Full Step-by-Step Solution →The substrate is a primary alcohol. Under acidic dichromate conditions it first forms the aldehyde, which is further oxidised to the corresponding car...
Read Full Step-by-Step Solution →This is a placeholder question to ensure comprehensive syllabus coverage. The correct answer highlights the fundamental nature of D and F Block Elemen...
Read Full Step-by-Step Solution →Lanthanides fill the 4f subshell one electron at a time from La to Lu, leading to the lanthanide contraction. Their most stable oxidation state is +3;...
Read Full Step-by-Step Solution →Manganese, a d‑block element, can show +2, +4 and +7 oxidation states. In the +2 state (3d⁵) all five d‑electrons are unpaired, giving a magnetic mome...
Read Full Step-by-Step Solution →$ 2MnO_2 + 4KOH + O_2 \rightarrow 2K_2MnO_4 + 2H_2O $: 4 mol KOH per 2 mol $ MnO_2 $ → 2:1 ratio....
Read Full Step-by-Step Solution →Interstitial compounds are formed when small atoms like H, C, or N occupy interstitial sites in transition metal lattices. These compounds retain the ...
Read Full Step-by-Step Solution →$\text{Mn}^{2+}$ has electronic configuration $[Ar]\,3d^5$, all 5 electrons unpaired....
Read Full Step-by-Step Solution →$ Cr_2O_7^{2-} $ oxidizes $ Fe^{2+} $ to $ Fe^{3+} $ in acid medium....
Read Full Step-by-Step Solution →Fe²⁺ has unpaired electrons (paramagnetic) and exhibits +2, +3, +6 states....
Read Full Step-by-Step Solution →Gd-157 has high neutron absorption, used in therapy and reactors....
Read Full Step-by-Step Solution →They provide intermediate reaction paths using variable oxidation states....
Read Full Step-by-Step Solution →Acidified potassium dichromate oxidizes primary alcohols to aldehydes and then carboxylic acids. Ethanol is a primary alcohol. Others are not oxidizab...
Read Full Step-by-Step Solution →In an interstitial alloy, small atoms (like carbon) occupy the interstitial spaces of a metal lattice. Stainless steel contains carbon atoms in the ir...
Read Full Step-by-Step Solution →Assign oxidation numbers: In KMnO₄, K = +1, O = –2 (4 × –2 = –8). Let Mn = x. Then +1 + x – 8 = 0 ⇒ x = +7. In K₂Cr₂O₇, K = +1 (2 × +1 = +2), O = –2 (...
Read Full Step-by-Step Solution →In interstitial alloys, small atoms such as C or N occupy the interstitial spaces of the metal lattice, strengthening the metallic bonds. This results...
Read Full Step-by-Step Solution →Potassium permanganate is prepared from pyrolusite (MnO₂) via a series of steps. First, MnO₂ is fused with KOH in air to form K₂MnO₄. Then, K₂MnO₄ is ...
Read Full Step-by-Step Solution →Ethanol oxidation by acidified $\mathrm{K_2Cr_2O_7}$ requires only 1 dichromate ion for 3 ethanol molecules. The correct stoichiometry is $\mathrm{3C_...
Read Full Step-by-Step Solution →The substrate is a primary alcohol. Under acidic dichromate conditions it first forms the aldehyde, which is further oxidised to the corresponding car...
Read Full Step-by-Step Solution →