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Home/JEE MAINS/chemistry/chemical bonding and molecular structure
Curated PYQ Collection

Top 50 Most Repeated CHEMICAL BONDING AND MOLECULAR STRUCTURE PYQs | JEE MAINS

A curated collection of the most important questions from CHEMICAL BONDING AND MOLECULAR STRUCTURE, fully solved with step-by-step concepts to prepare for JEE MAINS.

Question #1

Practice Question

A.$\text{CO}_2$
B.$\text{NH}_3$
C.$\text{CH}_4$
D.$\text{H}_2O$

Concept Applied

To determine the molecular geometry of a molecule, we use the VSEPR theory. The VSEPR theory states that the shape of a molecule is determined by the ...

Read Full Step-by-Step Solution →

Question #2

Practice Question

A.$\text{CH}_4$
B.$\text{BF}_3$
C.$\text{NH}_3$
D.$\text{CO}_2$

Concept Applied

$\text{NH}_3$ has pyramidal shape and high electronegativity difference....

Read Full Step-by-Step Solution →

Question #3

Practice Question

A.Tetrahedral
B.See-saw
C.Square planar
D.Trigonal bipyramidal

Concept Applied

Sulfur in $\mathrm{SF_4}$ has 6 valence electrons, forming 4 bonds and leaving 1 lone pair. The electron geometry is trigonal bipyramidal. The lone pa...

Read Full Step-by-Step Solution →

Question #4

Practice Question

A.$\text{CO}_2$
B.$\text{NH}_3$
C.$\text{CH}_4$
D.$\text{H}_2O$

Concept Applied

To determine the molecular geometry of a molecule, we use the VSEPR theory. The VSEPR theory states that the shape of a molecule is determined by the ...

Read Full Step-by-Step Solution →

Question #5

Practice Question

A.$\text{CH}_4$
B.$\text{BF}_3$
C.$\text{NH}_3$
D.$\text{CO}_2$

Concept Applied

$\text{NH}_3$ has pyramidal shape and high electronegativity difference....

Read Full Step-by-Step Solution →

Question #6

Practice Question

A.Tetrahedral
B.See-saw
C.Square planar
D.Trigonal bipyramidal

Concept Applied

Sulfur in $\mathrm{SF_4}$ has 6 valence electrons, forming 4 bonds and leaving 1 lone pair. The electron geometry is trigonal bipyramidal. The lone pa...

Read Full Step-by-Step Solution →

Question #7

Practice Question

A.$\text{CO}_2$
B.$\text{NH}_3$
C.$\text{CH}_4$
D.$\text{H}_2O$

Concept Applied

To determine the molecular geometry of a molecule, we use the VSEPR theory. The VSEPR theory states that the shape of a molecule is determined by the ...

Read Full Step-by-Step Solution →

Question #8

Practice Question

A.$\text{CH}_4$
B.$\text{BF}_3$
C.$\text{NH}_3$
D.$\text{CO}_2$

Concept Applied

$\text{NH}_3$ has pyramidal shape and high electronegativity difference....

Read Full Step-by-Step Solution →

Question #9

Practice Question

A.Tetrahedral
B.See-saw
C.Square planar
D.Trigonal bipyramidal

Concept Applied

Sulfur in $\mathrm{SF_4}$ has 6 valence electrons, forming 4 bonds and leaving 1 lone pair. The electron geometry is trigonal bipyramidal. The lone pa...

Read Full Step-by-Step Solution →

Question #10

Practice Question

A.$\text{CO}_2$
B.$\text{NH}_3$
C.$\text{CH}_4$
D.$\text{H}_2O$

Concept Applied

To determine the molecular geometry of a molecule, we use the VSEPR theory. The VSEPR theory states that the shape of a molecule is determined by the ...

Read Full Step-by-Step Solution →

Question #11

Practice Question

A.$\text{CH}_4$
B.$\text{BF}_3$
C.$\text{NH}_3$
D.$\text{CO}_2$

Concept Applied

$\text{NH}_3$ has pyramidal shape and high electronegativity difference....

Read Full Step-by-Step Solution →

Question #12

Practice Question

A.Tetrahedral
B.See-saw
C.Square planar
D.Trigonal bipyramidal

Concept Applied

Sulfur in $\mathrm{SF_4}$ has 6 valence electrons, forming 4 bonds and leaving 1 lone pair. The electron geometry is trigonal bipyramidal. The lone pa...

Read Full Step-by-Step Solution →

Question #13

Practice Question

A.$\text{CO}_2$
B.$\text{NH}_3$
C.$\text{CH}_4$
D.$\text{H}_2O$

Concept Applied

To determine the molecular geometry of a molecule, we use the VSEPR theory. The VSEPR theory states that the shape of a molecule is determined by the ...

Read Full Step-by-Step Solution →

Question #14

Practice Question

A.$\text{CH}_4$
B.$\text{BF}_3$
C.$\text{NH}_3$
D.$\text{CO}_2$

Concept Applied

$\text{NH}_3$ has pyramidal shape and high electronegativity difference....

Read Full Step-by-Step Solution →

Question #15

Practice Question

A.Tetrahedral
B.See-saw
C.Square planar
D.Trigonal bipyramidal

Concept Applied

Sulfur in $\mathrm{SF_4}$ has 6 valence electrons, forming 4 bonds and leaving 1 lone pair. The electron geometry is trigonal bipyramidal. The lone pa...

Read Full Step-by-Step Solution →

Question #16

Practice Question

A.$\text{CO}_2$
B.$\text{NH}_3$
C.$\text{CH}_4$
D.$\text{H}_2O$

Concept Applied

To determine the molecular geometry of a molecule, we use the VSEPR theory. The VSEPR theory states that the shape of a molecule is determined by the ...

Read Full Step-by-Step Solution →

Question #17

Practice Question

A.$\text{CH}_4$
B.$\text{BF}_3$
C.$\text{NH}_3$
D.$\text{CO}_2$

Concept Applied

$\text{NH}_3$ has pyramidal shape and high electronegativity difference....

Read Full Step-by-Step Solution →

Question #18

Practice Question

A.Tetrahedral
B.See-saw
C.Square planar
D.Trigonal bipyramidal

Concept Applied

Sulfur in $\mathrm{SF_4}$ has 6 valence electrons, forming 4 bonds and leaving 1 lone pair. The electron geometry is trigonal bipyramidal. The lone pa...

Read Full Step-by-Step Solution →

Question #19

Practice Question

A.$\text{CO}_2$
B.$\text{NH}_3$
C.$\text{CH}_4$
D.$\text{H}_2O$

Concept Applied

To determine the molecular geometry of a molecule, we use the VSEPR theory. The VSEPR theory states that the shape of a molecule is determined by the ...

Read Full Step-by-Step Solution →

Question #20

Practice Question

A.$\text{CH}_4$
B.$\text{BF}_3$
C.$\text{NH}_3$
D.$\text{CO}_2$

Concept Applied

$\text{NH}_3$ has pyramidal shape and high electronegativity difference....

Read Full Step-by-Step Solution →

Question #21

Practice Question

A.Tetrahedral
B.See-saw
C.Square planar
D.Trigonal bipyramidal

Concept Applied

Sulfur in $\mathrm{SF_4}$ has 6 valence electrons, forming 4 bonds and leaving 1 lone pair. The electron geometry is trigonal bipyramidal. The lone pa...

Read Full Step-by-Step Solution →

Question #22

Practice Question

A.$\text{CO}_2$
B.$\text{NH}_3$
C.$\text{CH}_4$
D.$\text{H}_2O$

Concept Applied

To determine the molecular geometry of a molecule, we use the VSEPR theory. The VSEPR theory states that the shape of a molecule is determined by the ...

Read Full Step-by-Step Solution →

Question #23

Practice Question

A.$\text{CH}_4$
B.$\text{BF}_3$
C.$\text{NH}_3$
D.$\text{CO}_2$

Concept Applied

$\text{NH}_3$ has pyramidal shape and high electronegativity difference....

Read Full Step-by-Step Solution →

Question #24

Practice Question

A.Tetrahedral
B.See-saw
C.Square planar
D.Trigonal bipyramidal

Concept Applied

Sulfur in $\mathrm{SF_4}$ has 6 valence electrons, forming 4 bonds and leaving 1 lone pair. The electron geometry is trigonal bipyramidal. The lone pa...

Read Full Step-by-Step Solution →
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