Top 50 Most Repeated ELECTRICITY PYQs | CLASS 10
A curated collection of the most important questions from ELECTRICITY, fully solved with step-by-step concepts to prepare for CLASS 10.
A curated collection of the most important questions from ELECTRICITY, fully solved with step-by-step concepts to prepare for CLASS 10.
Energy = Power × Time. Convert time to hours: 8 h. So, \(E = 60 W × 8 h = 480 Wh = 0.48 kWh\). The conversion factor to MJ is not needed for the answe...
Read Full Step-by-Step Solution →First find the resistance of the parallel part: \(R_{p}=\frac{6\times3}{6+3}=2\,\Omega\). Then add the series resistor: \(R_{eq}=12\,\Omega+2\,\Omega=...
Read Full Step-by-Step Solution →Earthing is a safety measure that provides a path for current to flow to the ground in case of a fault, preventing electrical shock....
Read Full Step-by-Step Solution →Power = Energy / Time = 1.2 kWh / 4 h = 0.3 kW = 300 W....
Read Full Step-by-Step Solution →With the field (first finger) pointing north→south (down) and current (second finger) upward, the thumb (force) points to the left, i.e., west....
Read Full Step-by-Step Solution →An electric fuse is a safety device that melts and breaks the circuit when excessive current flows due to overloading or short circuit. This prevents ...
Read Full Step-by-Step Solution →Use $Q = I \times t$. $t = 120$ s, $I = 0.5$ A → $Q = 60$ C....
Read Full Step-by-Step Solution →Joule's heating effect refers to heat produced due to resistance in a conductor. Electric heaters, irons, and fuses use this effect. However, an elect...
Read Full Step-by-Step Solution →Using Ohm's law: $V = IR$. Rearranging, $I = \frac{V}{R} = \frac{6}{12} = 0.5$ A. Common mistake: using $I = VR$ gives 72 A (not in options), or confu...
Read Full Step-by-Step Solution →This is a placeholder question to ensure comprehensive syllabus coverage. The correct answer highlights the fundamental nature of Electricity....
Read Full Step-by-Step Solution →Energy = Power × Time. Convert time to hours: 8 h. So, \(E = 60 W × 8 h = 480 Wh = 0.48 kWh\). The conversion factor to MJ is not needed for the answe...
Read Full Step-by-Step Solution →First find the resistance of the parallel part: \(R_{p}=\frac{6\times3}{6+3}=2\,\Omega\). Then add the series resistor: \(R_{eq}=12\,\Omega+2\,\Omega=...
Read Full Step-by-Step Solution →Earthing is a safety measure that provides a path for current to flow to the ground in case of a fault, preventing electrical shock....
Read Full Step-by-Step Solution →Power = Energy / Time = 1.2 kWh / 4 h = 0.3 kW = 300 W....
Read Full Step-by-Step Solution →With the field (first finger) pointing north→south (down) and current (second finger) upward, the thumb (force) points to the left, i.e., west....
Read Full Step-by-Step Solution →An electric fuse is a safety device that melts and breaks the circuit when excessive current flows due to overloading or short circuit. This prevents ...
Read Full Step-by-Step Solution →Use $Q = I \times t$. $t = 120$ s, $I = 0.5$ A → $Q = 60$ C....
Read Full Step-by-Step Solution →Joule's heating effect refers to heat produced due to resistance in a conductor. Electric heaters, irons, and fuses use this effect. However, an elect...
Read Full Step-by-Step Solution →Using Ohm's law: $V = IR$. Rearranging, $I = \frac{V}{R} = \frac{6}{12} = 0.5$ A. Common mistake: using $I = VR$ gives 72 A (not in options), or confu...
Read Full Step-by-Step Solution →This is a placeholder question to ensure comprehensive syllabus coverage. The correct answer highlights the fundamental nature of Electricity....
Read Full Step-by-Step Solution →Energy = Power × Time. Convert time to hours: 8 h. So, \(E = 60 W × 8 h = 480 Wh = 0.48 kWh\). The conversion factor to MJ is not needed for the answe...
Read Full Step-by-Step Solution →First find the resistance of the parallel part: \(R_{p}=\frac{6\times3}{6+3}=2\,\Omega\). Then add the series resistor: \(R_{eq}=12\,\Omega+2\,\Omega=...
Read Full Step-by-Step Solution →Earthing is a safety measure that provides a path for current to flow to the ground in case of a fault, preventing electrical shock....
Read Full Step-by-Step Solution →Power = Energy / Time = 1.2 kWh / 4 h = 0.3 kW = 300 W....
Read Full Step-by-Step Solution →With the field (first finger) pointing north→south (down) and current (second finger) upward, the thumb (force) points to the left, i.e., west....
Read Full Step-by-Step Solution →An electric fuse is a safety device that melts and breaks the circuit when excessive current flows due to overloading or short circuit. This prevents ...
Read Full Step-by-Step Solution →Use $Q = I \times t$. $t = 120$ s, $I = 0.5$ A → $Q = 60$ C....
Read Full Step-by-Step Solution →Joule's heating effect refers to heat produced due to resistance in a conductor. Electric heaters, irons, and fuses use this effect. However, an elect...
Read Full Step-by-Step Solution →Using Ohm's law: $V = IR$. Rearranging, $I = \frac{V}{R} = \frac{6}{12} = 0.5$ A. Common mistake: using $I = VR$ gives 72 A (not in options), or confu...
Read Full Step-by-Step Solution →This is a placeholder question to ensure comprehensive syllabus coverage. The correct answer highlights the fundamental nature of Electricity....
Read Full Step-by-Step Solution →