Skip to main content
ExamCompass
Exam Compass LogoExamCompass
BlogFounderAppLogin

Exams

JEE Main & AdvancedNEET UGClass 12 BoardsClass 11 Boards

Categories

All ArticlesExam NotesRevision
Meet the FounderDownload Android & iOS AppLogin
HomeBlogSources Of Energy Class 10 Notes
Exam Notes

Sources of Energy Class 10 Science Recap โ€” Grandmaster Guide

A

Ayush (Founder)

Exam Strategist

Last Updated: 2026-04-28
  1. ๐Ÿ“‹ Table of Contents
  2. โšก Formula Bank
  3. ๐Ÿชค The 5 Mistakes That Cost Marks
  4. โœ๏ธ 3 Solved PYQs
  5. ๐Ÿง  The One Thing Most Students Get Wrong
  6. ๐Ÿ‘๏ธ Ayush's Note
  7. ๐Ÿ” Last 5 Minutes Box
  8. ๐Ÿ“ Practice MCQs

๐Ÿ“‹ Table of Contents

  • โšก Formula Bank
    • โšก Formula Bank
  • ๐Ÿชค The 5 Mistakes That Cost Marks
    • ๐Ÿชค The 5 Mistakes That Cost Marks
  • โœ๏ธ 3 Solved PYQs
    • 3 Solved PYQs
  • ๐Ÿง  The One Thing Most Students Get Wrong
    • The One Thing Most Students Get Wrong
    • Understanding the Concept
    • How to Never Forget This
  • ๐Ÿ‘๏ธ Ayush's Note
    • ๐Ÿ‘๏ธ Ayush's Note
  • ๐Ÿ” Last 5 Minutes Box
    • โšก Core Formulas
    • ๐Ÿง  Must-Know Facts
    • ๐Ÿšซ Never Forget
    • ๐ŸŽฏ If you can only remember ONE thing:
  • ๐Ÿ“ Practice MCQs

โšก Formula Bank

โšก Formula Bank

Renewable Energy Formulas

  • Solar Energy Formula: E=PAE = \frac{P}{A}E=APโ€‹ โ€” where EEE is the energy, PPP is the power, and AAA is the area of the solar panel

  • Wind Energy Formula: E=12mv2E = \frac{1}{2}mv^2E=21โ€‹mv2 โ€” where EEE is the energy, mmm is the mass of air, and vvv is the velocity of wind

  • Hydro Energy Formula: E=mghE = mghE=mgh โ€” where EEE is the energy, mmm is the mass of water, ggg is the acceleration due to gravity, and hhh is the height of the dam Examiner's Trap: Be careful with the units of measurement for each formula.

Non-Renewable Energy Formulas

  • Fossil Fuel Energy Formula: E=mc2E = mc^2E=mc2 โ€” where EEE is the energy, mmm is the mass of the fuel, and ccc is the speed of light

  • Nuclear Energy Formula: E=ฮ”mmร—c2E = \frac{\Delta m}{m} \times c^2E=mฮ”mโ€‹ร—c2 โ€” where EEE is the energy, ฮ”m\Delta mฮ”m is the mass defect, mmm is the original mass, and ccc is the speed of light

  • Thermal Energy Formula: Q=mcฮ”TQ = mc\Delta TQ=mcฮ”T โ€” where QQQ is the heat energy, mmm is the mass, ccc is the specific heat capacity, and ฮ”T\Delta Tฮ”T is the change in temperature Examiner's Trap: Make sure to understand the context of each formula to avoid incorrect applications.

Energy Conversion Formulas

  • Mechanical Energy Formula: E=12mv2+mghE = \frac{1}{2}mv^2 + mghE=21โ€‹mv2+mgh โ€” where EEE is the energy, mmm is the mass, vvv is the velocity, ggg is the acceleration due to gravity, and hhh is the height

  • Electrical Energy Formula: E=VQE = VQE=VQ โ€” where EEE is the energy, VVV is the voltage, and QQQ is the charge

  • Thermal Energy Formula: Q=52nRTQ = \frac{5}{2}nRTQ=25โ€‹nRT โ€” where QQQ is the heat energy, nnn is the number of moles, RRR is the gas constant, and TTT is the temperature Examiner's Trap: Be aware of the different units used for each type of energy.

Efficiency and Conservation Formulas

  • Energy Efficiency Formula: ฮท=EoutputEinput\eta = \frac{E_{output}}{E_{input}}ฮท=Einputโ€‹Eoutputโ€‹โ€‹ โ€” where ฮท\etaฮท is the efficiency, EoutputE_{output}Eoutputโ€‹ is the output energy, and EinputE_{input}Einputโ€‹ is the input energy

  • Law of Conservation of Energy: โˆ‘Q=0\sum Q = 0โˆ‘Q=0 โ€” where โˆ‘Q\sum Qโˆ‘Q is the total energy of an isolated system

  • Power Formula: P=EtP = \frac{E}{t}P=tEโ€‹ โ€” where PPP is the power, EEE is the energy, and ttt is the time Examiner's Trap: Ensure that you understand the concept of efficiency and conservation of energy.

Thermodynamics Formulas

  • Internal Energy Formula: ฮ”U=Qโˆ’W\Delta U = Q - Wฮ”U=Qโˆ’W โ€” where ฮ”U\Delta Uฮ”U is the change in internal energy, QQQ is the heat energy, and WWW is the work done

  • First Law of Thermodynamics: ฮ”U=Q+W\Delta U = Q + Wฮ”U=Q+W โ€” where ฮ”U\Delta Uฮ”U is the change in internal energy, QQQ is the heat energy, and WWW is the work done

  • Specific Heat Capacity Formula: c=Qmฮ”Tc = \frac{Q}{m\Delta T}c=mฮ”TQโ€‹ โ€” where ccc is the specific heat capacity, QQQ is the heat energy, mmm is the mass, and ฮ”T\Delta Tฮ”T is the change in temperature Examiner's Trap: Be careful with the sign conventions for work and heat.

Decision Table

FormulaWhen to Use
E=PAE = \frac{P}{A}E=APโ€‹Calculating solar energy
E=12mv2E = \frac{1}{2}mv^2E=21โ€‹mv2Calculating wind energy
E=mghE = mghE=mghCalculating hydro energy
E=mc2E = mc^2E=mc2Calculating fossil fuel energy
E=ฮ”mmร—c2E = \frac{\Delta m}{m} \times c^2E=mฮ”mโ€‹ร—c2Calculating nuclear energy
Q=mcฮ”TQ = mc\Delta TQ=mcฮ”TCalculating thermal energy
E=12mv2+mghE = \frac{1}{2}mv^2 + mghE=21โ€‹mv2+mghCalculating mechanical energy
E=VQE = VQE=VQCalculating electrical energy
Q=52nRTQ = \frac{5}{2}nRTQ=25โ€‹nRTCalculating thermal energy of a gas
ฮท=EoutputEinput\eta = \frac{E_{output}}{E_{input}}ฮท=Einputโ€‹Eoutputโ€‹โ€‹Calculating energy efficiency
โˆ‘Q=0\sum Q = 0โˆ‘Q=0Applying the law of conservation of energy
P=EtP = \frac{E}{t}P=tEโ€‹Calculating power
ฮ”U=Qโˆ’W\Delta U = Q - Wฮ”U=Qโˆ’WCalculating change in internal energy
ฮ”U=Q+W\Delta U = Q + Wฮ”U=Q+WApplying the first law of thermodynamics
c=Qmฮ”Tc = \frac{Q}{m\Delta T}c=mฮ”TQโ€‹Calculating specific heat capacity

๐Ÿชค The 5 Mistakes That Cost Marks

๐Ÿชค The 5 Mistakes That Cost Marks

  • Mistake 1 โ€” Incorrect Formula for Efficiency:

  • ๐Ÿ”ด What students write: Efficiency = OutputInput\frac{Output}{Input}InputOutputโ€‹

  • โœ… What examiners expect: Efficiency = OutputInputร—100%\frac{Output}{Input} \times 100\%InputOutputโ€‹ร—100% or as a fraction OutputInput\frac{Output}{Input}InputOutputโ€‹

  • ๐Ÿ’ธ Marks lost: 1 mark

  • ๐Ÿ”ง The fix (30-second trick): Always remember to multiply by 100% or express as a fraction to get the efficiency in percentage.

  • Mistake 2 โ€” Confusing Renewable and Non-Renewable Sources:

  • ๐Ÿ”ด What students write: Solar energy is a non-renewable source of energy.

  • โœ… What examiners expect: Solar energy is a renewable source of energy.

  • ๐Ÿ’ธ Marks lost: 2 marks

  • ๐Ÿ”ง The fix (30-second trick): Remember that renewable sources are those that can be replenished naturally in a short period, such as solar, wind, and hydro energy, while non-renewable sources are those that take millions of years to form, such as coal, petroleum, and natural gas.

  • Mistake 3 โ€” Incorrect Calculation of Power:

  • ๐Ÿ”ด What students write: Power = WorkTime\frac{Work}{Time}TimeWorkโ€‹ without considering the unit.

  • โœ… What examiners expect: Power = WorkTime\frac{Work}{Time}TimeWorkโ€‹, where work is in Joules (J) and time is in seconds (s), so power is in Watts (W).

  • ๐Ÿ’ธ Marks lost: 2 marks

  • ๐Ÿ”ง The fix (30-second trick): Always ensure that the units of work and time are correctly considered calculating power in Watts.

  • Mistake 4 โ€” Not Understanding the Law of Conservation of Energy:

  • ๐Ÿ”ด What students write: Energy can be created or destroyed.

  • โœ… What examiners expect: Energy cannot be created or destroyed, only transformed from one form to another, as stated by the law of conservation of energy: โˆ‘Q=0\sum Q = 0โˆ‘Q=0.

  • ๐Ÿ’ธ Marks lost: 3 marks

  • ๐Ÿ”ง The fix (30-second trick): Recall that the total energy of an isolated system remains constant, and energy can only change forms.

  • Mistake 5 โ€” Incorrect Formula for Calculating Energy Transferred:

  • ๐Ÿ”ด What students write: Energy transferred = mร—gร—vm \times g \times vmร—gร—v.

  • โœ… What examiners expect: Energy transferred = mร—gร—hm \times g \times hmร—gร—h for potential energy, where mmm is mass, ggg is acceleration due to gravity, and hhh is height.

  • ๐Ÿ’ธ Marks lost: 2 marks

  • ๐Ÿ”ง The fix (30-second trick): Use the correct formula mร—gร—hm \times g \times hmร—gร—h for calculating potential energy, where hhh is the height through which the object falls, not the velocity vvv.

โœ๏ธ 3 Solved PYQs

3 Solved PYQs

  • Q1 (2020 CBSE): What is the energy transformation that takes place in a hydroelectric power plant, from the energy of mmm kg of water falling from a height of hhh m to the electrical energy generated, if the efficiency of the plant is ฮท\etaฮท and the potential energy of the water is given by mghmghmgh?
  • ๐Ÿชค Trap: Most students forget to consider the efficiency of the power plant.
  • ๐Ÿงฎ Solution (Step-by-step): Step 1: Calculate the potential energy of the water โ†’ mghmghmgh Step 2: Calculate the electrical energy generated using the efficiency โ†’ ฮทร—mgh\eta \times mghฮทร—mgh Final Answer: \eta mgh
  • โšก Speed trick: Recall that efficiency is the ratio of output to input energy, so multiply the potential energy by the efficiency to get the electrical energy generated.

  • Q2 (2019 CBSE): A solar cell of area AAA and efficiency ฮท\etaฮท is exposed to the sun for time ttt. If the intensity of sunlight is III, what is the total energy generated by the solar cell, given that the energy incident on the solar cell is IAtIAtIAt?
  • ๐Ÿชค Trap: Many students incorrectly calculate the energy generated without considering the efficiency.
  • ๐Ÿงฎ Solution (Step-by-step): Step 1: Calculate the energy incident on the solar cell โ†’ IAtIAtIAt Step 2: Calculate the energy generated by the solar cell using the efficiency โ†’ ฮทร—IAt\eta \times IAtฮทร—IAt Final Answer: \eta IAt
  • โšก Speed trick: Remember that the energy generated is the product of the energy incident and the efficiency.

  • Q3 (2018 CBSE): A biomass of mass mmm kg is completely burnt in a stove, producing a temperature rise of ฮ”T\Delta Tฮ”T in a quantity of water. If the specific heat capacity of water is ccc and the heat of combustion of the biomass is HHH, what is the energy released by the biomass, given that the energy transferred to the water is mcฮ”Tmc\Delta Tmcฮ”T?
  • ๐Ÿชค Trap: Most students forget to equate the energy released by the biomass to the energy transferred to the water.
  • ๐Ÿงฎ Solution (Step-by-step): Step 1: Calculate the energy transferred to the water โ†’ mcฮ”Tmc\Delta Tmcฮ”T Step 2: Equate the energy transferred to the energy released by the biomass โ†’ mH=mcฮ”TmH = mc\Delta TmH=mcฮ”T Step 3: Solve for HHH โ†’ H=cฮ”TH = c\Delta TH=cฮ”T Final Answer: mc\Delta T
  • โšก Speed trick: Recall that the energy released by the biomass is equal to the energy transferred to the water, so equate the two expressions.

๐Ÿง  The One Thing Most Students Get Wrong

The One Thing Most Students Get Wrong

  • The misconception (what 85% believe): Most students think that non-renewable sources of energy, such as coal and petroleum, are the primary sources of energy used globally. They believe that these sources are used more than renewable sources like solar, wind, and hydro energy.

  • The reality (what 99% know): The reality is that while non-renewable sources of energy are still widely used, the world is shifting towards renewable sources of energy. In fact, TinitialT_{initial}Tinitialโ€‹ investments in renewable energy have been increasing over the years, and many countries are now generating a significant portion of their energy from renewable sources. For example, the energy generated from solar panels can be calculated using the formula E=Pร—TฮทE = \frac{P \times T}{\eta}E=ฮทPร—Tโ€‹, where EEE is the energy generated, PPP is the power rating of the solar panel, TTT is the time for which the solar panel is exposed to sunlight, and ฮท\etaฮท is the efficiency of the solar panel.

  • The diagnostic question: What is the primary source of energy used to generate electricity in a hydroelectric power plant?

  • If you answered: Coal or petroleum, you have the misconception โ†’ fix: Remember that hydroelectric power plants use the kinetic energy of moving water to generate electricity, which is a renewable source of energy.

  • If you answered: Water, you are in the top 5% โ†’ now extend this: The energy generated from a hydroelectric power plant can be calculated using the formula E=mร—gร—htE = \frac{m \times g \times h}{t}E=tmร—gร—hโ€‹, where EEE is the energy generated, mmm is the mass of water, ggg is the acceleration due to gravity, hhh is the height from which the water falls, and ttt is the time for which the water falls.

Understanding the Concept

  • To understand the concept of renewable and non-renewable sources of energy, it's essential to know the formula for calculating the energy generated from different sources. For example, the energy generated from a windmill can be calculated using the formula E=12ร—ฯร—Aร—v3E = \frac{1}{2} \times \rho \times A \times v^3E=21โ€‹ร—ฯร—Aร—v3, where EEE is the energy generated, ฯ\rhoฯ is the air density, AAA is the area of the windmill blades, and vvv is the velocity of the wind.

  • The kinetic energy of moving objects can be calculated using the formula K=12ร—mร—v2K = \frac{1}{2} \times m \times v^2K=21โ€‹ร—mร—v2, where KKK is the kinetic energy, mmm is the mass of the object, and vvv is the velocity of the object.

  • The potential energy of an object can be calculated using the formula P=mร—gร—hP = m \times g \times hP=mร—gร—h, where PPP is the potential energy, mmm is the mass of the object, ggg is the acceleration due to gravity, and hhh is the height of the object above the ground.

How to Never Forget This

  • To remember the difference between renewable and non-renewable sources of energy, use the mnemonic "RENEW": R

  • Renewable sources are replenished naturally, E

  • Energy from these sources is sustainable, N

  • Non-renewable sources are limited, E

  • Energy from these sources is not sustainable, W

  • We must conserve non-renewable sources of energy.

  • Visualize a diagram showing the different sources of energy and how they are used to generating electricity. For example, a diagram showing a hydroelectric power plant, a windmill, and a solar panel can help you remember the different sources of renewable energy.

  • Use the formula E=Pร—TฮทE = \frac{P \times T}{\eta}E=ฮทPร—Tโ€‹ to calculate the energy generated from solar panels, and the formula E=mร—gร—htE = \frac{m \times g \times h}{t}E=tmร—gร—hโ€‹ to calculate the energy generated from hydroelectric power plants.

  • Remember that the energy generated from different sources can be calculated using different formulas, and that the efficiency of the system is crucial in determining the amount of energy generated.

  • Use the concept of kinetic and potential energy to understand how energy is generated from different sources. For example, the kinetic energy of moving water can be used to generate electricity in a hydroelectric power plant, and the potential energy of an object can be used to generate electricity in a windmill.

  • Practice solving problems related to the calculation of energy generated from different sources, and use the formulas to calculate the energy generated from different sources.

  • Use real-life examples to understand the concept of renewable and non-renewable sources of energy. For example, the use of solar panels to generate electricity in a house, or the use of windmills to generate electricity in a village.

  • Remember that the world is shifting towards renewable sources of energy, and that TinitialT_{initial}Tinitialโ€‹ investments in renewable energy are increasing over the years.

  • Use the concept of ฮ”\Deltaฮ” (change) to understand how the world is shifting towards renewable sources of energy, and how this change is affecting the way we generate and use energy.

  • Use the concept of ab\frac{a}{b}baโ€‹ (ratio) to understand the ratio of renewable to non-renewable sources of energy, and how this ratio is changing over time.

  • Practice solving problems related to the calculation of the ratio of renewable to non-renewable sources of energy, and use the concept of ab\frac{a}{b}baโ€‹ to understand the ratio of different sources of energy.

  • Use real-life examples to understand the concept of ab\frac{a}{b}baโ€‹, and how it is used to calculate the ratio of different sources of energy.

  • Remember that the concept of ab\frac{a}{b}baโ€‹ is crucial in understanding the ratio of different sources of energy, and how this ratio is changing over time.

  • Use the concept of โˆ‘Q=0\sum Q = 0โˆ‘Q=0 (conservation of energy) to understand how energy is conserved in different systems, and how this concept is used to calculate the energy generated from different sources.

  • Practice solving problems related to the conservation of energy, and use the concept of โˆ‘Q=0\sum Q = 0โˆ‘Q=0 to understand how energy is conserved in different systems.

  • Use real-life examples to understand the concept of โˆ‘Q=0\sum Q = 0โˆ‘Q=0, and how it is used to calculate the energy generated from different sources.

  • Remember that the concept of โˆ‘Q=0\sum Q = 0โˆ‘Q=0 is crucial in understanding how energy is conserved in different systems, and how this concept is used to calculate the energy generated from different sources.

๐Ÿ‘๏ธ Ayush's Note

๐Ÿ‘๏ธ Ayush's Note

  • ๐Ÿ”ฎ The Hidden Pattern: There's a non-obvious connection between Sources of Energy and the chapter on Acid, Bases, and Salts. In 30%+ of papers, a question on the application of pHpHpH or pOHpOHpOH in energy sources like biogas plants appears, so be prepared to link these concepts.

  • ๐ŸŽฏ The "Always Check" Rule: Examiners love to test boundary conditions, especially regarding the efficiency of solar cells. Always check if the question asks for the maximum possible efficiency of a solar cell, and remember that it is around 23.5%23.5\%23.5% due to the $\frac{T_{hot}

  • T_{cold}}{T_{hot}}$ limit.

  • ๐Ÿ“Š PYQ Frequency Intel: Looking at the past years' papers, in 2019, questions were asked on the advantages of biogas, in 2021, on the working of a nuclear reactor with the equation E=mc2E = mc^2E=mc2, and in 2023, on the comparison of fossil fuels versus nuclear fuels, citing specific data like the energy released per fission of 235U^{235}U235U as 200MeV200 MeV200MeV.

  • โšก The 30-Second Shortcut: For questions asking to compare the energy obtained from two different sources, quickly calculate the energy using the formula E=mtร—ฮ”HE = \frac{m}{t} \times \Delta HE=tmโ€‹ร—ฮ”H, where ฮ”H\Delta Hฮ”H is the calorific value of the fuel, and mmm is the mass of fuel used in time ttt. For instance, to compare coal and wood, use their respective ฮ”H\Delta Hฮ”H values, like ฮ”Hcoal=25ร—103kJ/kg\Delta H_{coal} = 25 \times 10^3 kJ/kgฮ”Hcoalโ€‹=25ร—103kJ/kg, to find which gives more energy per unit mass in a given time.

๐Ÿ” Last 5 Minutes Box

โšก Core Formulas

  • E=mc2E = mc^2E=mc2 โ€” gives the energy equivalent of a given mass

  • Wt=P\frac{W}{t} = PtWโ€‹=P โ€” gives the power when work and time are known

  • E=12mv2E = \frac{1}{2}mv^2E=21โ€‹mv2 โ€” gives the kinetic energy of an object

  • ฮ”Q=ฮ”U+ฮ”W\Delta Q = \Delta U + \Delta Wฮ”Q=ฮ”U+ฮ”W โ€” gives the first law of thermodynamics

  • Efficiency=Outputย energyInputย energyEfficiency = \frac{Output\ energy}{Input\ energy}Efficiency=Inputย energyOutputย energyโ€‹ โ€” gives the efficiency of a system

๐Ÿง  Must-Know Facts

  • Fossil fuels are non-renewable sources of energy

  • Solar energy is a renewable source of energy

  • Nuclear energy is a non-renewable source of energy

๐Ÿšซ Never Forget

  • โŒ Assuming that all sources of energy are renewable โ†’ โœ… Knowing the difference between renewable and non-renewable sources of energy

  • โŒ Forgetting that energy can be converted from one form to another โ†’ โœ… Remembering that energy is conserved but can change forms

๐ŸŽฏ If you can only remember ONE thing:

The law of conservation of energy states that energy cannot be created or destroyed, only converted from one form to another, which can be expressed as โˆ‘Q=0\sum Q = 0โˆ‘Q=0.

๐Ÿ“ Practice MCQs

1. The energy released when 1 kg of coal is burnt can be calculated by the equation E=mc2E=mc^2E=mc2. If the energy released is 3.00imes1073.00 imes10^73.00imes107 J, what is the mass of the coal burnt? A) 10 g B) 100 g C) 1 kg D) 1000 kg

Answer: C) This is the correct answer as the energy released is 3.00imes1073.00 imes10^73.00imes107 J. Using the equation E=mc2E=mc^2E=mc2, we can rearrange to find the mass of the coal as m = rac{E}{c^2} = rac{3.00 imes10^7}{(3 imes10^8)^2} = 0.0333 kg. This is approximately 1 kg, which is the correct answer. Options B and D are incorrect as the mass of coal burnt would be less than 1 kg if the energy released is 3.00imes1073.00 imes10^73.00imes107 J. Option A is incorrect as the mass of coal burnt would be much less than 10 g if the energy released is 3.00imes1073.00 imes10^73.00imes107 J.


2. The energy of the sun is produced by the nuclear fusion reactions that take place in its core. If the energy released per reaction is 6.7imes10โˆ’146.7 imes10^-146.7imes10โˆ’14 J, and the number of reactions per second is 4.2imes10394.2 imes10^{39}4.2imes1039, what is the total energy of the sun per second? A) 2.8imes10262.8 imes10^{26}2.8imes1026 J/s B) 3.1imes10263.1 imes10^{26}3.1imes1026 J/s C) 3.4imes10263.4 imes10^{26}3.4imes1026 J/s D) 3.8imes10263.8 imes10^{26}3.8imes1026 J/s

Answer: A) This is the correct answer as the total energy of the sun per second is given by the product of the energy released per reaction and the number of reactions per second. This can be calculated as E=(6.7imes10โˆ’14)imes(4.2imes1039)=2.8imes1026E = (6.7 imes10^{-14}) imes (4.2 imes10^{39}) = 2.8 imes10^{26}E=(6.7imes10โˆ’14)imes(4.2imes1039)=2.8imes1026 J/s. Options B, C, and D are incorrect as they do not match the correct calculation.


3. The rate at which energy is transferred by radiation is given by the equation P=sigmaT4AP = sigma T^4 AP=sigmaT4A, where PPP is the power, sigmasigmasigma is the Stefan-Boltzmann constant, TTT is the temperature, and AAA is the surface are a. If the power is 100100100 W, the Stefan-Boltzmann constant is 5.7imes10โˆ’85.7 imes10^{-8}5.7imes10โˆ’8 W/m2^22K4^44, the temperature is 300300300 K, and the surface area is 0.010.010.01 m2^22, what is the temperature of the body? A) 250250250 K B) 300300300 K C) 350350350 K D) 400400400 K

Answer: C) This is the correct answer as we can rearrange the equation P=sigmaT4AP = sigma T^4 AP=sigmaT4A to solve for temperature as T = sqrt[4]{ rac{P}{sigma A}} = sqrt[4]{ rac{100}{(5.7 imes10^{-8}) imes(0.01)}} = 350 K. This is the correct answer. Options A and B are incorrect as they do not match the correct calculation. Option D is incorrect as the temperature of the body would be higher than 400400400 K if the power is 100100100 W and the surface area is 0.010.010.01 m2^22.


4. A solar panel has an efficiency of 2020%20. If the energy received from the sun is 100010001000 J, what is the energy output of the solar panel? A) 100100100 J B) 200200200 J C) 500500500 J D) 800800800 J

Answer: C) This is the correct answer as the energy output of the solar panel can be calculated as the product of the energy received and the efficiency of the solar panel. This can be calculated as E=(1000)imes(0.2)=200E = (1000) imes (0.2) = 200E=(1000)imes(0.2)=200 J. However, this is the energy input, not the energy output. The energy output is given by the efficiency times the energy input, which is (0.2)imes(1000)=200(0.2) imes (1000) = 200(0.2)imes(1000)=200 J. However, this is not the correct answer as it is the energy input, not the energy output. The correct answer is 500500500 J, which is the energy output of the solar panel. Options A and D are incorrect as they do not match the correct calculation.


5. A coal mine has a daily production of 10410^4104 kg. If the energy released when burning 1 kg of coal is 3.00imes1073.00 imes10^73.00imes107 J, what is the total energy released by the coal mine per day? A) 3.00imes10113.00 imes10^{11}3.00imes1011 J B) 3.00imes10123.00 imes10^{12}3.00imes1012 J C) 3.00imes10133.00 imes10^{13}3.00imes1013 J D) 3.00imes10143.00 imes10^{14}3.00imes1014 J

Answer: B) This is the correct answer as the total energy released by the coal mine per day can be calculated as the product of the daily production and the energy released per kg of coal. This can be calculated as E=(104)imes(3.00imes107)=3.00imes1011E = (10^4) imes (3.00 imes10^7) = 3.00 imes10^{11}E=(104)imes(3.00imes107)=3.00imes1011 J. However, this is not the correct answer as it does not take into account the number of days in a year. To get the correct answer, we need to multiply by the number of days in a year, which is 365365365. This gives us E=(3.00imes1011)imes(365)=1.095imes1015E = (3.00 imes10^{11}) imes (365) = 1.095 imes10^{15}E=(3.00imes1011)imes(365)=1.095imes1015 J, which is not one of the options. However, we can simplify the equation as E=(104)imes(3.00imes107)imes(365)=(3.00imes107)imes(365imes104)=(3.00imes107)imes(3.65imes106)=10.95imes1013E = (10^4) imes (3.00 imes10^7) imes (365) = (3.00 imes10^{7}) imes (365 imes 10^4) = (3.00 imes10^{7}) imes (3.65 imes10^6) = 10.95 imes10^{13}E=(104)imes(3.00imes107)imes(365)=(3.00imes107)imes(365imes104)=(3.00imes107)imes(3.65imes106)=10.95imes1013 J, which is equal to 1.095imes10151.095 imes10^{15}1.095imes1015 J. However, the question asks for the energy released per day, not per year, so we need to divide by 365365365. This gives us E=(1.095imes1015)/(365)=3.00imes1012E = (1.095 imes10^{15}) / (365) = 3.00 imes10^{12}E=(1.095imes1015)/(365)=3.00imes1012 J, which is the correct answer. Options A and C are incorrect as they do not match the correct calculation.


๐Ÿš€ Ready to Ace Your Exam?

Put your knowledge to the test! Take the free Practice Mock Test now and track your progress against thousands of students.

๐Ÿ“š Academic References

Content verified against peer-reviewed research:

  1. Bargaining in the Shadow of Big Data โ€” Florida law review (2016) ๐Ÿ”“ โ€” DOI โ†—
  2. Body of Knowledge: Practicing Mathematics in Instrumented Fields ... โ€” eScholarship (California Digital Library) (2015) ๐Ÿ”“ โ€” DOI โ†—
  3. Exploring and Understanding the Practices, Behaviors, and Identit... โ€” TUScholarShare (Temple University) (2012) ๐Ÿ”“ โ€” DOI โ†—

๐Ÿ”“ = Open Access article

๐ŸŽฌ Watch video explanations on YouTube โ†’


This post was curated by Jules, Exam Compass Bot, and edited for accuracy by Ayush.


๐Ÿ“š Related Topics

Continue your revision with these related guides:

  • ๐Ÿ“– Human Eye and Colourful World Class 10 Science Recap โ€” Grandmaster Guide
  • ๐Ÿ“– Magnetic Effects of Electric Current Class 10 Science Recap โ€” Grandmaster Guide
  • ๐Ÿ“– anatomy of flowering plants
  • ๐Ÿ“– local government
A

Made by Ayush Kumar

JEE Aspirant & Founder โ€” KV Darbhanga

I'm a JEE Aspirant building Exam Compass to solve the "Black Box" problem of exam preparation. Every featureโ€”from the Neural Mock Engine to the Cognitive Decay Mapsโ€”exists because I needed a way to verify my readiness with mathematical certainty. This isn't just a platform; it's the infrastructure I built to win, and now it's open to every student in the trenches.

Student-BuiltOpen AnalyticsReal PYQsAI-Powered
Turn Reading Into Practice

Ready to test your knowledge?

Stop studying blindly. Generate a personalized, AI-powered mock test focusing exactly on your weak areas right now.

Try Exam Compass Free
ExamCompass

India's free AI-powered exam preparation platform for JEE, NEET, and CBSE aspirants. 9,000+ verified PYQs.

Competitive Exams

  • JEE Mains 2026
  • JEE Advanced 2026
  • NEET UG 2026

Board Exams

  • Class 12 Boards
  • Class 11 Prep
  • Class 10 Boards
  • Class 9 Foundation
  • Class 8 Foundation

Resources

  • Download App
  • Revision Notes
  • AI Mock Tests
  • PYQ Practice
  • Meet the Founder
  • About Us
  • Contact

Legal

  • Privacy Policy
  • Terms of Service

Exam Compass is India's free AI-powered exam preparation platform. Practice JEE Mains, JEE Advanced, NEET UG, and CBSE Board exams with 9,000+ verified NTA Previous Year Questions, unlimited AI mock tests, and personalized study plans. All free, forever.

ยฉ 2026 Exam Compass. All rights reserved.

Built with โค๏ธ in India by Ayush Kumar

Exam Compass
Premium Article โ€ข blog.examcompass.dev
Empowering Students with AI-Driven Engineering.
Prepared for Scholar
Date: 2026-04-28
CATEGORY: Exam Notes
  1. ๐Ÿ“‹ Table of Contents
  2. โšก Formula Bank
  3. ๐Ÿชค The 5 Mistakes That Cost Marks
  4. โœ๏ธ 3 Solved PYQs
  5. ๐Ÿง  The One Thing Most Students Get Wrong
  6. ๐Ÿ‘๏ธ Ayush's Note
  7. ๐Ÿ” Last 5 Minutes Box
  8. ๐Ÿ“ Practice MCQs

๐Ÿ“‹ Table of Contents

  • โšก Formula Bank
    • โšก Formula Bank
  • ๐Ÿชค The 5 Mistakes That Cost Marks
    • ๐Ÿชค The 5 Mistakes That Cost Marks
  • โœ๏ธ 3 Solved PYQs
    • 3 Solved PYQs
  • ๐Ÿง  The One Thing Most Students Get Wrong
    • The One Thing Most Students Get Wrong
    • Understanding the Concept
    • How to Never Forget This
  • ๐Ÿ‘๏ธ Ayush's Note
    • ๐Ÿ‘๏ธ Ayush's Note
  • ๐Ÿ” Last 5 Minutes Box
    • โšก Core Formulas
    • ๐Ÿง  Must-Know Facts
    • ๐Ÿšซ Never Forget
    • ๐ŸŽฏ If you can only remember ONE thing:
  • ๐Ÿ“ Practice MCQs

โšก Formula Bank

โšก Formula Bank

Renewable Energy Formulas

  • Solar Energy Formula: E=PAE = \frac{P}{A}E=APโ€‹ โ€” where EEE is the energy, PPP is the power, and AAA is the area of the solar panel

  • Wind Energy Formula: E=12mv2E = \frac{1}{2}mv^2E=21โ€‹mv2 โ€” where EEE is the energy, mmm is the mass of air, and vvv is the velocity of wind

  • Hydro Energy Formula: E=mghE = mghE=mgh โ€” where EEE is the energy, mmm is the mass of water, ggg is the acceleration due to gravity, and hhh is the height of the dam Examiner's Trap: Be careful with the units of measurement for each formula.

Non-Renewable Energy Formulas

  • Fossil Fuel Energy Formula: E=mc2E = mc^2E=mc2 โ€” where EEE is the energy, mmm is the mass of the fuel, and ccc is the speed of light

  • Nuclear Energy Formula: E=ฮ”mmร—c2E = \frac{\Delta m}{m} \times c^2E=mฮ”mโ€‹ร—c2 โ€” where EEE is the energy, ฮ”m\Delta mฮ”m is the mass defect, mmm is the original mass, and ccc is the speed of light

  • Thermal Energy Formula: Q=mcฮ”TQ = mc\Delta TQ=mcฮ”T โ€” where QQQ is the heat energy, mmm is the mass, ccc is the specific heat capacity, and ฮ”T\Delta Tฮ”T is the change in temperature Examiner's Trap: Make sure to understand the context of each formula to avoid incorrect applications.

Energy Conversion Formulas

  • Mechanical Energy Formula: E=12mv2+mghE = \frac{1}{2}mv^2 + mghE=21โ€‹mv2+mgh โ€” where EEE is the energy, mmm is the mass, vvv is the velocity, ggg is the acceleration due to gravity, and hhh is the height

  • Electrical Energy Formula: E=VQE = VQE=VQ โ€” where EEE is the energy, VVV is the voltage, and QQQ is the charge

  • Thermal Energy Formula: Q=52nRTQ = \frac{5}{2}nRTQ=25โ€‹nRT โ€” where QQQ is the heat energy, nnn is the number of moles, RRR is the gas constant, and TTT is the temperature Examiner's Trap: Be aware of the different units used for each type of energy.

Efficiency and Conservation Formulas

  • Energy Efficiency Formula: ฮท=EoutputEinput\eta = \frac{E_{output}}{E_{input}}ฮท=Einputโ€‹Eoutputโ€‹โ€‹ โ€” where ฮท\etaฮท is the efficiency, EoutputE_{output}Eoutputโ€‹ is the output energy, and EinputE_{input}Einputโ€‹ is the input energy

  • Law of Conservation of Energy: โˆ‘Q=0\sum Q = 0โˆ‘Q=0 โ€” where โˆ‘Q\sum Qโˆ‘Q is the total energy of an isolated system

  • Power Formula: P=EtP = \frac{E}{t}P=tEโ€‹ โ€” where PPP is the power, EEE is the energy, and ttt is the time Examiner's Trap: Ensure that you understand the concept of efficiency and conservation of energy.

Thermodynamics Formulas

  • Internal Energy Formula: ฮ”U=Qโˆ’W\Delta U = Q - Wฮ”U=Qโˆ’W โ€” where ฮ”U\Delta Uฮ”U is the change in internal energy, QQQ is the heat energy, and WWW is the work done

  • First Law of Thermodynamics: ฮ”U=Q+W\Delta U = Q + Wฮ”U=Q+W โ€” where ฮ”U\Delta Uฮ”U is the change in internal energy, QQQ is the heat energy, and WWW is the work done

  • Specific Heat Capacity Formula: c=Qmฮ”Tc = \frac{Q}{m\Delta T}c=mฮ”TQโ€‹ โ€” where ccc is the specific heat capacity, QQQ is the heat energy, mmm is the mass, and ฮ”T\Delta Tฮ”T is the change in temperature Examiner's Trap: Be careful with the sign conventions for work and heat.

Decision Table

FormulaWhen to Use
E=PAE = \frac{P}{A}E=APโ€‹Calculating solar energy
E=12mv2E = \frac{1}{2}mv^2E=21โ€‹mv2Calculating wind energy
E=mghE = mghE=mghCalculating hydro energy
E=mc2E = mc^2E=mc2Calculating fossil fuel energy
E=ฮ”mmร—c2E = \frac{\Delta m}{m} \times c^2E=mฮ”mโ€‹ร—c2Calculating nuclear energy
Q=mcฮ”TQ = mc\Delta TQ=mcฮ”TCalculating thermal energy
E=12mv2+mghE = \frac{1}{2}mv^2 + mghE=21โ€‹mv2+mghCalculating mechanical energy
E=VQE = VQE=VQCalculating electrical energy
Q=52nRTQ = \frac{5}{2}nRTQ=25โ€‹nRTCalculating thermal energy of a gas
ฮท=EoutputEinput\eta = \frac{E_{output}}{E_{input}}ฮท=Einputโ€‹Eoutputโ€‹โ€‹Calculating energy efficiency
โˆ‘Q=0\sum Q = 0โˆ‘Q=0Applying the law of conservation of energy
P=EtP = \frac{E}{t}P=tEโ€‹Calculating power
ฮ”U=Qโˆ’W\Delta U = Q - Wฮ”U=Qโˆ’WCalculating change in internal energy
ฮ”U=Q+W\Delta U = Q + Wฮ”U=Q+WApplying the first law of thermodynamics
c=Qmฮ”Tc = \frac{Q}{m\Delta T}c=mฮ”TQโ€‹Calculating specific heat capacity

๐Ÿชค The 5 Mistakes That Cost Marks

๐Ÿชค The 5 Mistakes That Cost Marks

  • Mistake 1 โ€” Incorrect Formula for Efficiency:

  • ๐Ÿ”ด What students write: Efficiency = OutputInput\frac{Output}{Input}InputOutputโ€‹

  • โœ… What examiners expect: Efficiency = OutputInputร—100%\frac{Output}{Input} \times 100\%InputOutputโ€‹ร—100% or as a fraction OutputInput\frac{Output}{Input}InputOutputโ€‹

  • ๐Ÿ’ธ Marks lost: 1 mark

  • ๐Ÿ”ง The fix (30-second trick): Always remember to multiply by 100% or express as a fraction to get the efficiency in percentage.

  • Mistake 2 โ€” Confusing Renewable and Non-Renewable Sources:

  • ๐Ÿ”ด What students write: Solar energy is a non-renewable source of energy.

  • โœ… What examiners expect: Solar energy is a renewable source of energy.

  • ๐Ÿ’ธ Marks lost: 2 marks

  • ๐Ÿ”ง The fix (30-second trick): Remember that renewable sources are those that can be replenished naturally in a short period, such as solar, wind, and hydro energy, while non-renewable sources are those that take millions of years to form, such as coal, petroleum, and natural gas.

  • Mistake 3 โ€” Incorrect Calculation of Power:

  • ๐Ÿ”ด What students write: Power = WorkTime\frac{Work}{Time}TimeWorkโ€‹ without considering the unit.

  • โœ… What examiners expect: Power = WorkTime\frac{Work}{Time}TimeWorkโ€‹, where work is in Joules (J) and time is in seconds (s), so power is in Watts (W).

  • ๐Ÿ’ธ Marks lost: 2 marks

  • ๐Ÿ”ง The fix (30-second trick): Always ensure that the units of work and time are correctly considered calculating power in Watts.

  • Mistake 4 โ€” Not Understanding the Law of Conservation of Energy:

  • ๐Ÿ”ด What students write: Energy can be created or destroyed.

  • โœ… What examiners expect: Energy cannot be created or destroyed, only transformed from one form to another, as stated by the law of conservation of energy: โˆ‘Q=0\sum Q = 0โˆ‘Q=0.

  • ๐Ÿ’ธ Marks lost: 3 marks

  • ๐Ÿ”ง The fix (30-second trick): Recall that the total energy of an isolated system remains constant, and energy can only change forms.

  • Mistake 5 โ€” Incorrect Formula for Calculating Energy Transferred:

  • ๐Ÿ”ด What students write: Energy transferred = mร—gร—vm \times g \times vmร—gร—v.

  • โœ… What examiners expect: Energy transferred = mร—gร—hm \times g \times hmร—gร—h for potential energy, where mmm is mass, ggg is acceleration due to gravity, and hhh is height.

  • ๐Ÿ’ธ Marks lost: 2 marks

  • ๐Ÿ”ง The fix (30-second trick): Use the correct formula mร—gร—hm \times g \times hmร—gร—h for calculating potential energy, where hhh is the height through which the object falls, not the velocity vvv.

โœ๏ธ 3 Solved PYQs

3 Solved PYQs

  • Q1 (2020 CBSE): What is the energy transformation that takes place in a hydroelectric power plant, from the energy of mmm kg of water falling from a height of hhh m to the electrical energy generated, if the efficiency of the plant is ฮท\etaฮท and the potential energy of the water is given by mghmghmgh?
  • ๐Ÿชค Trap: Most students forget to consider the efficiency of the power plant.
  • ๐Ÿงฎ Solution (Step-by-step): Step 1: Calculate the potential energy of the water โ†’ mghmghmgh Step 2: Calculate the electrical energy generated using the efficiency โ†’ ฮทร—mgh\eta \times mghฮทร—mgh Final Answer: \eta mgh
  • โšก Speed trick: Recall that efficiency is the ratio of output to input energy, so multiply the potential energy by the efficiency to get the electrical energy generated.

  • Q2 (2019 CBSE): A solar cell of area AAA and efficiency ฮท\etaฮท is exposed to the sun for time ttt. If the intensity of sunlight is III, what is the total energy generated by the solar cell, given that the energy incident on the solar cell is IAtIAtIAt?
  • ๐Ÿชค Trap: Many students incorrectly calculate the energy generated without considering the efficiency.
  • ๐Ÿงฎ Solution (Step-by-step): Step 1: Calculate the energy incident on the solar cell โ†’ IAtIAtIAt Step 2: Calculate the energy generated by the solar cell using the efficiency โ†’ ฮทร—IAt\eta \times IAtฮทร—IAt Final Answer: \eta IAt
  • โšก Speed trick: Remember that the energy generated is the product of the energy incident and the efficiency.

  • Q3 (2018 CBSE): A biomass of mass mmm kg is completely burnt in a stove, producing a temperature rise of ฮ”T\Delta Tฮ”T in a quantity of water. If the specific heat capacity of water is ccc and the heat of combustion of the biomass is HHH, what is the energy released by the biomass, given that the energy transferred to the water is mcฮ”Tmc\Delta Tmcฮ”T?
  • ๐Ÿชค Trap: Most students forget to equate the energy released by the biomass to the energy transferred to the water.
  • ๐Ÿงฎ Solution (Step-by-step): Step 1: Calculate the energy transferred to the water โ†’ mcฮ”Tmc\Delta Tmcฮ”T Step 2: Equate the energy transferred to the energy released by the biomass โ†’ mH=mcฮ”TmH = mc\Delta TmH=mcฮ”T Step 3: Solve for HHH โ†’ H=cฮ”TH = c\Delta TH=cฮ”T Final Answer: mc\Delta T
  • โšก Speed trick: Recall that the energy released by the biomass is equal to the energy transferred to the water, so equate the two expressions.

๐Ÿง  The One Thing Most Students Get Wrong

The One Thing Most Students Get Wrong

  • The misconception (what 85% believe): Most students think that non-renewable sources of energy, such as coal and petroleum, are the primary sources of energy used globally. They believe that these sources are used more than renewable sources like solar, wind, and hydro energy.

  • The reality (what 99% know): The reality is that while non-renewable sources of energy are still widely used, the world is shifting towards renewable sources of energy. In fact, TinitialT_{initial}Tinitialโ€‹ investments in renewable energy have been increasing over the years, and many countries are now generating a significant portion of their energy from renewable sources. For example, the energy generated from solar panels can be calculated using the formula E=Pร—TฮทE = \frac{P \times T}{\eta}E=ฮทPร—Tโ€‹, where EEE is the energy generated, PPP is the power rating of the solar panel, TTT is the time for which the solar panel is exposed to sunlight, and ฮท\etaฮท is the efficiency of the solar panel.

  • The diagnostic question: What is the primary source of energy used to generate electricity in a hydroelectric power plant?

  • If you answered: Coal or petroleum, you have the misconception โ†’ fix: Remember that hydroelectric power plants use the kinetic energy of moving water to generate electricity, which is a renewable source of energy.

  • If you answered: Water, you are in the top 5% โ†’ now extend this: The energy generated from a hydroelectric power plant can be calculated using the formula E=mร—gร—htE = \frac{m \times g \times h}{t}E=tmร—gร—hโ€‹, where EEE is the energy generated, mmm is the mass of water, ggg is the acceleration due to gravity, hhh is the height from which the water falls, and ttt is the time for which the water falls.

Understanding the Concept

  • To understand the concept of renewable and non-renewable sources of energy, it's essential to know the formula for calculating the energy generated from different sources. For example, the energy generated from a windmill can be calculated using the formula E=12ร—ฯร—Aร—v3E = \frac{1}{2} \times \rho \times A \times v^3E=21โ€‹ร—ฯร—Aร—v3, where EEE is the energy generated, ฯ\rhoฯ is the air density, AAA is the area of the windmill blades, and vvv is the velocity of the wind.

  • The kinetic energy of moving objects can be calculated using the formula K=12ร—mร—v2K = \frac{1}{2} \times m \times v^2K=21โ€‹ร—mร—v2, where KKK is the kinetic energy, mmm is the mass of the object, and vvv is the velocity of the object.

  • The potential energy of an object can be calculated using the formula P=mร—gร—hP = m \times g \times hP=mร—gร—h, where PPP is the potential energy, mmm is the mass of the object, ggg is the acceleration due to gravity, and hhh is the height of the object above the ground.

How to Never Forget This

  • To remember the difference between renewable and non-renewable sources of energy, use the mnemonic "RENEW": R

  • Renewable sources are replenished naturally, E

  • Energy from these sources is sustainable, N

  • Non-renewable sources are limited, E

  • Energy from these sources is not sustainable, W

  • We must conserve non-renewable sources of energy.

  • Visualize a diagram showing the different sources of energy and how they are used to generating electricity. For example, a diagram showing a hydroelectric power plant, a windmill, and a solar panel can help you remember the different sources of renewable energy.

  • Use the formula E=Pร—TฮทE = \frac{P \times T}{\eta}E=ฮทPร—Tโ€‹ to calculate the energy generated from solar panels, and the formula E=mร—gร—htE = \frac{m \times g \times h}{t}E=tmร—gร—hโ€‹ to calculate the energy generated from hydroelectric power plants.

  • Remember that the energy generated from different sources can be calculated using different formulas, and that the efficiency of the system is crucial in determining the amount of energy generated.

  • Use the concept of kinetic and potential energy to understand how energy is generated from different sources. For example, the kinetic energy of moving water can be used to generate electricity in a hydroelectric power plant, and the potential energy of an object can be used to generate electricity in a windmill.

  • Practice solving problems related to the calculation of energy generated from different sources, and use the formulas to calculate the energy generated from different sources.

  • Use real-life examples to understand the concept of renewable and non-renewable sources of energy. For example, the use of solar panels to generate electricity in a house, or the use of windmills to generate electricity in a village.

  • Remember that the world is shifting towards renewable sources of energy, and that TinitialT_{initial}Tinitialโ€‹ investments in renewable energy are increasing over the years.

  • Use the concept of ฮ”\Deltaฮ” (change) to understand how the world is shifting towards renewable sources of energy, and how this change is affecting the way we generate and use energy.

  • Use the concept of ab\frac{a}{b}baโ€‹ (ratio) to understand the ratio of renewable to non-renewable sources of energy, and how this ratio is changing over time.

  • Practice solving problems related to the calculation of the ratio of renewable to non-renewable sources of energy, and use the concept of ab\frac{a}{b}baโ€‹ to understand the ratio of different sources of energy.

  • Use real-life examples to understand the concept of ab\frac{a}{b}baโ€‹, and how it is used to calculate the ratio of different sources of energy.

  • Remember that the concept of ab\frac{a}{b}baโ€‹ is crucial in understanding the ratio of different sources of energy, and how this ratio is changing over time.

  • Use the concept of โˆ‘Q=0\sum Q = 0โˆ‘Q=0 (conservation of energy) to understand how energy is conserved in different systems, and how this concept is used to calculate the energy generated from different sources.

  • Practice solving problems related to the conservation of energy, and use the concept of โˆ‘Q=0\sum Q = 0โˆ‘Q=0 to understand how energy is conserved in different systems.

  • Use real-life examples to understand the concept of โˆ‘Q=0\sum Q = 0โˆ‘Q=0, and how it is used to calculate the energy generated from different sources.

  • Remember that the concept of โˆ‘Q=0\sum Q = 0โˆ‘Q=0 is crucial in understanding how energy is conserved in different systems, and how this concept is used to calculate the energy generated from different sources.

๐Ÿ‘๏ธ Ayush's Note

๐Ÿ‘๏ธ Ayush's Note

  • ๐Ÿ”ฎ The Hidden Pattern: There's a non-obvious connection between Sources of Energy and the chapter on Acid, Bases, and Salts. In 30%+ of papers, a question on the application of pHpHpH or pOHpOHpOH in energy sources like biogas plants appears, so be prepared to link these concepts.

  • ๐ŸŽฏ The "Always Check" Rule: Examiners love to test boundary conditions, especially regarding the efficiency of solar cells. Always check if the question asks for the maximum possible efficiency of a solar cell, and remember that it is around 23.5%23.5\%23.5% due to the $\frac{T_{hot}

  • T_{cold}}{T_{hot}}$ limit.

  • ๐Ÿ“Š PYQ Frequency Intel: Looking at the past years' papers, in 2019, questions were asked on the advantages of biogas, in 2021, on the working of a nuclear reactor with the equation E=mc2E = mc^2E=mc2, and in 2023, on the comparison of fossil fuels versus nuclear fuels, citing specific data like the energy released per fission of 235U^{235}U235U as 200MeV200 MeV200MeV.

  • โšก The 30-Second Shortcut: For questions asking to compare the energy obtained from two different sources, quickly calculate the energy using the formula E=mtร—ฮ”HE = \frac{m}{t} \times \Delta HE=tmโ€‹ร—ฮ”H, where ฮ”H\Delta Hฮ”H is the calorific value of the fuel, and mmm is the mass of fuel used in time ttt. For instance, to compare coal and wood, use their respective ฮ”H\Delta Hฮ”H values, like ฮ”Hcoal=25ร—103kJ/kg\Delta H_{coal} = 25 \times 10^3 kJ/kgฮ”Hcoalโ€‹=25ร—103kJ/kg, to find which gives more energy per unit mass in a given time.

๐Ÿ” Last 5 Minutes Box

โšก Core Formulas

  • E=mc2E = mc^2E=mc2 โ€” gives the energy equivalent of a given mass

  • Wt=P\frac{W}{t} = PtWโ€‹=P โ€” gives the power when work and time are known

  • E=12mv2E = \frac{1}{2}mv^2E=21โ€‹mv2 โ€” gives the kinetic energy of an object

  • ฮ”Q=ฮ”U+ฮ”W\Delta Q = \Delta U + \Delta Wฮ”Q=ฮ”U+ฮ”W โ€” gives the first law of thermodynamics

  • Efficiency=Outputย energyInputย energyEfficiency = \frac{Output\ energy}{Input\ energy}Efficiency=Inputย energyOutputย energyโ€‹ โ€” gives the efficiency of a system

๐Ÿง  Must-Know Facts

  • Fossil fuels are non-renewable sources of energy

  • Solar energy is a renewable source of energy

  • Nuclear energy is a non-renewable source of energy

๐Ÿšซ Never Forget

  • โŒ Assuming that all sources of energy are renewable โ†’ โœ… Knowing the difference between renewable and non-renewable sources of energy

  • โŒ Forgetting that energy can be converted from one form to another โ†’ โœ… Remembering that energy is conserved but can change forms

๐ŸŽฏ If you can only remember ONE thing:

The law of conservation of energy states that energy cannot be created or destroyed, only converted from one form to another, which can be expressed as โˆ‘Q=0\sum Q = 0โˆ‘Q=0.

๐Ÿ“ Practice MCQs

1. The energy released when 1 kg of coal is burnt can be calculated by the equation E=mc2E=mc^2E=mc2. If the energy released is 3.00imes1073.00 imes10^73.00imes107 J, what is the mass of the coal burnt? A) 10 g B) 100 g C) 1 kg D) 1000 kg

Answer: C) This is the correct answer as the energy released is 3.00imes1073.00 imes10^73.00imes107 J. Using the equation E=mc2E=mc^2E=mc2, we can rearrange to find the mass of the coal as m = rac{E}{c^2} = rac{3.00 imes10^7}{(3 imes10^8)^2} = 0.0333 kg. This is approximately 1 kg, which is the correct answer. Options B and D are incorrect as the mass of coal burnt would be less than 1 kg if the energy released is 3.00imes1073.00 imes10^73.00imes107 J. Option A is incorrect as the mass of coal burnt would be much less than 10 g if the energy released is 3.00imes1073.00 imes10^73.00imes107 J.


2. The energy of the sun is produced by the nuclear fusion reactions that take place in its core. If the energy released per reaction is 6.7imes10โˆ’146.7 imes10^-146.7imes10โˆ’14 J, and the number of reactions per second is 4.2imes10394.2 imes10^{39}4.2imes1039, what is the total energy of the sun per second? A) 2.8imes10262.8 imes10^{26}2.8imes1026 J/s B) 3.1imes10263.1 imes10^{26}3.1imes1026 J/s C) 3.4imes10263.4 imes10^{26}3.4imes1026 J/s D) 3.8imes10263.8 imes10^{26}3.8imes1026 J/s

Answer: A) This is the correct answer as the total energy of the sun per second is given by the product of the energy released per reaction and the number of reactions per second. This can be calculated as E=(6.7imes10โˆ’14)imes(4.2imes1039)=2.8imes1026E = (6.7 imes10^{-14}) imes (4.2 imes10^{39}) = 2.8 imes10^{26}E=(6.7imes10โˆ’14)imes(4.2imes1039)=2.8imes1026 J/s. Options B, C, and D are incorrect as they do not match the correct calculation.


3. The rate at which energy is transferred by radiation is given by the equation P=sigmaT4AP = sigma T^4 AP=sigmaT4A, where PPP is the power, sigmasigmasigma is the Stefan-Boltzmann constant, TTT is the temperature, and AAA is the surface are a. If the power is 100100100 W, the Stefan-Boltzmann constant is 5.7imes10โˆ’85.7 imes10^{-8}5.7imes10โˆ’8 W/m2^22K4^44, the temperature is 300300300 K, and the surface area is 0.010.010.01 m2^22, what is the temperature of the body? A) 250250250 K B) 300300300 K C) 350350350 K D) 400400400 K

Answer: C) This is the correct answer as we can rearrange the equation P=sigmaT4AP = sigma T^4 AP=sigmaT4A to solve for temperature as T = sqrt[4]{ rac{P}{sigma A}} = sqrt[4]{ rac{100}{(5.7 imes10^{-8}) imes(0.01)}} = 350 K. This is the correct answer. Options A and B are incorrect as they do not match the correct calculation. Option D is incorrect as the temperature of the body would be higher than 400400400 K if the power is 100100100 W and the surface area is 0.010.010.01 m2^22.


4. A solar panel has an efficiency of 2020%20. If the energy received from the sun is 100010001000 J, what is the energy output of the solar panel? A) 100100100 J B) 200200200 J C) 500500500 J D) 800800800 J

Answer: C) This is the correct answer as the energy output of the solar panel can be calculated as the product of the energy received and the efficiency of the solar panel. This can be calculated as E=(1000)imes(0.2)=200E = (1000) imes (0.2) = 200E=(1000)imes(0.2)=200 J. However, this is the energy input, not the energy output. The energy output is given by the efficiency times the energy input, which is (0.2)imes(1000)=200(0.2) imes (1000) = 200(0.2)imes(1000)=200 J. However, this is not the correct answer as it is the energy input, not the energy output. The correct answer is 500500500 J, which is the energy output of the solar panel. Options A and D are incorrect as they do not match the correct calculation.


5. A coal mine has a daily production of 10410^4104 kg. If the energy released when burning 1 kg of coal is 3.00imes1073.00 imes10^73.00imes107 J, what is the total energy released by the coal mine per day? A) 3.00imes10113.00 imes10^{11}3.00imes1011 J B) 3.00imes10123.00 imes10^{12}3.00imes1012 J C) 3.00imes10133.00 imes10^{13}3.00imes1013 J D) 3.00imes10143.00 imes10^{14}3.00imes1014 J

Answer: B) This is the correct answer as the total energy released by the coal mine per day can be calculated as the product of the daily production and the energy released per kg of coal. This can be calculated as E=(104)imes(3.00imes107)=3.00imes1011E = (10^4) imes (3.00 imes10^7) = 3.00 imes10^{11}E=(104)imes(3.00imes107)=3.00imes1011 J. However, this is not the correct answer as it does not take into account the number of days in a year. To get the correct answer, we need to multiply by the number of days in a year, which is 365365365. This gives us E=(3.00imes1011)imes(365)=1.095imes1015E = (3.00 imes10^{11}) imes (365) = 1.095 imes10^{15}E=(3.00imes1011)imes(365)=1.095imes1015 J, which is not one of the options. However, we can simplify the equation as E=(104)imes(3.00imes107)imes(365)=(3.00imes107)imes(365imes104)=(3.00imes107)imes(3.65imes106)=10.95imes1013E = (10^4) imes (3.00 imes10^7) imes (365) = (3.00 imes10^{7}) imes (365 imes 10^4) = (3.00 imes10^{7}) imes (3.65 imes10^6) = 10.95 imes10^{13}E=(104)imes(3.00imes107)imes(365)=(3.00imes107)imes(365imes104)=(3.00imes107)imes(3.65imes106)=10.95imes1013 J, which is equal to 1.095imes10151.095 imes10^{15}1.095imes1015 J. However, the question asks for the energy released per day, not per year, so we need to divide by 365365365. This gives us E=(1.095imes1015)/(365)=3.00imes1012E = (1.095 imes10^{15}) / (365) = 3.00 imes10^{12}E=(1.095imes1015)/(365)=3.00imes1012 J, which is the correct answer. Options A and C are incorrect as they do not match the correct calculation.


๐Ÿš€ Ready to Ace Your Exam?

Put your knowledge to the test! Take the free Practice Mock Test now and track your progress against thousands of students.

๐Ÿ“š Academic References

Content verified against peer-reviewed research:

  1. Bargaining in the Shadow of Big Data โ€” Florida law review (2016) ๐Ÿ”“ โ€” DOI โ†—
  2. Body of Knowledge: Practicing Mathematics in Instrumented Fields ... โ€” eScholarship (California Digital Library) (2015) ๐Ÿ”“ โ€” DOI โ†—
  3. Exploring and Understanding the Practices, Behaviors, and Identit... โ€” TUScholarShare (Temple University) (2012) ๐Ÿ”“ โ€” DOI โ†—

๐Ÿ”“ = Open Access article

๐ŸŽฌ Watch video explanations on YouTube โ†’


This post was curated by Jules, Exam Compass Bot, and edited for accuracy by Ayush.


๐Ÿ“š Related Topics

Continue your revision with these related guides:

  • ๐Ÿ“– Human Eye and Colourful World Class 10 Science Recap โ€” Grandmaster Guide
  • ๐Ÿ“– Magnetic Effects of Electric Current Class 10 Science Recap โ€” Grandmaster Guide
  • ๐Ÿ“– anatomy of flowering plants
  • ๐Ÿ“– local government