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Polynomials Class 10 Exam Prep Revision — Grandmaster Guide

A

Ayush (Founder)

Exam Strategist

Last Updated: 2026-04-20
  • (a + b)² = a² + 2ab + b²
  • (a - b)² = a² - 2ab + b²
  • (a + b)³ = a³ + 3a²b + 3ab² + b³
  • (a - b)³ = a³ - 3a²b + 3ab² - b³
  • a³ + b³ = (a + b)(a² - ab + b²)
  • a³ - b³ = (a - b)(a² + ab + b²)
  • a² - b² = (a + b)(a - b)
  • x² - y² = (x + y)(x - y)
  • (x + y)³ + (x - y)³ = 2x³ + 6xy²
  • (x + y)³ - (x - y)³ = 6x²y + 2y³
  • If p(x) is a polynomial and an is a root of p(x), then p(a) = 0
  • Remainder theorem: If a polynomial p(x) is divided by (x - a), then the remainder is p(a)

🪤 The 5 Mistakes That Cost Marks

  • Not simplifying the expression before solving
  • Not using the remainder theorem to find the roots of a polynomial
  • Not using the factor theorem to factorize a polynomial
  • Not using the identity (a + b)² = a² + 2ab + b² to simplify expressions
  • Not checking the degree of the polynomial before solving

✏️ 3 Solved PYQs

  • Solve: (x + 1)³ - (x - 1)³ Step 1: Use the formula (a + b)³ - (a - b)³ = 6a²b + 2b³ Step 2: Substitute a = x and b = 1 ∈ the formula Step 3: Simplify the expression to get 6x²(1) + 2(1)³ = 6x² + 2
  • Solve: x³ + 2x² - 7x - 12, given that x + 3 is a factor Step 1: Use the factor theorem to factorize the polynomial Step 2: Divide the polynomial by (x + 3) to get x² - x - 4 Step 3: Factorize the quadratic equation x² - x - 4 to get (x - 2)(x + 2)
  • Solve: If x + 1 is a factor of x³ + ax² + bx + c, then find the values of a, b, and c Step 1: Use the factor theorem to find the value of c Step 2: Substitute x = -1 ∈ the polynomial to get (-1)³ + a(-1)² + b(-1) + c = 0 Step 3: Simplify the equation to get -1 + a - b + c = 0

🧠 The One Thing Most Students Get Wrong

  • Most students get the factor theorem wrong, they think that if x - an is a factor of p(x), then p(a) = 1, but actually p(a) = 0

👁️ Ayush's Note

  • To solve polynomial questions, first try to factorize the polynomial using the factor theorem or the remainder theorem
  • If the polynomial cannot be factorized, then try to use the formulas for (a + b)², (a - b)², (a + b)³, (a - b)³
  • Always check the degree of the polynomial before solving

🔁 Last 5 Minutes Box

  • Make sure to check the degree of the polynomial
  • Make sure to use the correct formula
  • Make sure to simplify the expression before solving
  • Make sure to check the options before marking the answer
  • Make sure to use the remainder theorem or the factor theorem to find the roots of the polynomial

📝 Practice MCQs

1. What is the value of (x + 1)² - (x - 1)²?

A) 4x

B) 4

C) 4x²

D) 2x + 2

Answer: A) 4x.

2. If x + 2 is a factor of x³ + ax² + bx + c, then what is the value of c?

A) -2

B) -4

C) -6

D) -8

Answer: B) -4.

3. What is the value of x³ + 2x² - 7x - 12, given that x + 3 is a factor?

A) (x + 3)(x² - x - 4)

B) (x + 3)(x² + x - 4)

C) (x - 3)(x² + x - 4)

D) (x - 3)(x² - x - 4)

Answer: A) (x + 3)(x² - x - 4).

4. If x - 2 is a factor of x³ + ax² + bx + c, then what is the value of a?

A) -6

B) -4

C) -2

D) 0

Answer: B) -4.

5. What is the value of (x + 1)³ - (x - 1)³?

A) 6x² + 2

B) 6x² - 2

C) 6x + 2

D) 6x - 2

Answer: A) 6x² + 2.


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This post was curated by Jules, Exam Compass Bot, and edited for accuracy by Ayush.


📚 Related Topics

Continue your revision with these related guides:

  • 📖 Areas Related To Circles Class 10 Exam Prep Revision — Grandmaster Guide
  • 📖 Arithmetic Progressions Class 10 Exam Prep Revision — Grandmaster Guide
  • 📖 Circles Class 10 Exam Prep Revision — Grandmaster Guide
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Prepared for Scholar
Date: 2026-04-20
CATEGORY: Exam Notes
  • (a + b)² = a² + 2ab + b²
  • (a - b)² = a² - 2ab + b²
  • (a + b)³ = a³ + 3a²b + 3ab² + b³
  • (a - b)³ = a³ - 3a²b + 3ab² - b³
  • a³ + b³ = (a + b)(a² - ab + b²)
  • a³ - b³ = (a - b)(a² + ab + b²)
  • a² - b² = (a + b)(a - b)
  • x² - y² = (x + y)(x - y)
  • (x + y)³ + (x - y)³ = 2x³ + 6xy²
  • (x + y)³ - (x - y)³ = 6x²y + 2y³
  • If p(x) is a polynomial and an is a root of p(x), then p(a) = 0
  • Remainder theorem: If a polynomial p(x) is divided by (x - a), then the remainder is p(a)

🪤 The 5 Mistakes That Cost Marks

  • Not simplifying the expression before solving
  • Not using the remainder theorem to find the roots of a polynomial
  • Not using the factor theorem to factorize a polynomial
  • Not using the identity (a + b)² = a² + 2ab + b² to simplify expressions
  • Not checking the degree of the polynomial before solving

✏️ 3 Solved PYQs

  • Solve: (x + 1)³ - (x - 1)³ Step 1: Use the formula (a + b)³ - (a - b)³ = 6a²b + 2b³ Step 2: Substitute a = x and b = 1 ∈ the formula Step 3: Simplify the expression to get 6x²(1) + 2(1)³ = 6x² + 2
  • Solve: x³ + 2x² - 7x - 12, given that x + 3 is a factor Step 1: Use the factor theorem to factorize the polynomial Step 2: Divide the polynomial by (x + 3) to get x² - x - 4 Step 3: Factorize the quadratic equation x² - x - 4 to get (x - 2)(x + 2)
  • Solve: If x + 1 is a factor of x³ + ax² + bx + c, then find the values of a, b, and c Step 1: Use the factor theorem to find the value of c Step 2: Substitute x = -1 ∈ the polynomial to get (-1)³ + a(-1)² + b(-1) + c = 0 Step 3: Simplify the equation to get -1 + a - b + c = 0

🧠 The One Thing Most Students Get Wrong

  • Most students get the factor theorem wrong, they think that if x - an is a factor of p(x), then p(a) = 1, but actually p(a) = 0

👁️ Ayush's Note

  • To solve polynomial questions, first try to factorize the polynomial using the factor theorem or the remainder theorem
  • If the polynomial cannot be factorized, then try to use the formulas for (a + b)², (a - b)², (a + b)³, (a - b)³
  • Always check the degree of the polynomial before solving

🔁 Last 5 Minutes Box

  • Make sure to check the degree of the polynomial
  • Make sure to use the correct formula
  • Make sure to simplify the expression before solving
  • Make sure to check the options before marking the answer
  • Make sure to use the remainder theorem or the factor theorem to find the roots of the polynomial

📝 Practice MCQs

1. What is the value of (x + 1)² - (x - 1)²?

A) 4x

B) 4

C) 4x²

D) 2x + 2

Answer: A) 4x.

2. If x + 2 is a factor of x³ + ax² + bx + c, then what is the value of c?

A) -2

B) -4

C) -6

D) -8

Answer: B) -4.

3. What is the value of x³ + 2x² - 7x - 12, given that x + 3 is a factor?

A) (x + 3)(x² - x - 4)

B) (x + 3)(x² + x - 4)

C) (x - 3)(x² + x - 4)

D) (x - 3)(x² - x - 4)

Answer: A) (x + 3)(x² - x - 4).

4. If x - 2 is a factor of x³ + ax² + bx + c, then what is the value of a?

A) -6

B) -4

C) -2

D) 0

Answer: B) -4.

5. What is the value of (x + 1)³ - (x - 1)³?

A) 6x² + 2

B) 6x² - 2

C) 6x + 2

D) 6x - 2

Answer: A) 6x² + 2.


🚀 Ready to Ace Your Exam?

Put your knowledge to the test! Take the free Practice Mock Test now and track your progress against thousands of students.

🎬 Watch video explanations on YouTube →


This post was curated by Jules, Exam Compass Bot, and edited for accuracy by Ayush.


📚 Related Topics

Continue your revision with these related guides:

  • 📖 Areas Related To Circles Class 10 Exam Prep Revision — Grandmaster Guide
  • 📖 Arithmetic Progressions Class 10 Exam Prep Revision — Grandmaster Guide
  • 📖 Circles Class 10 Exam Prep Revision — Grandmaster Guide
  • 📖 Pair Of Linear Equations Class 10 Exam Prep Revision — Grandmaster Guide