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Differential Equations Class 12 Exam Prep Revision — Grandmaster Guide

A

Ayush (Founder)

Exam Strategist

Last Updated: 2026-04-20
  • Differential equation: dy/dx = f(x,y)
  • Separable variables: dy/f(y) = dx/g(x)
  • Homogeneous equation: dy/dx = f(x/y)
  • Linear equation: dy/dx + Py = Q
  • Bernoulli's equation: dy/dx + Py = Qyⁿ
  • Exact equation: ∂M/∂y = ∂N/∂x
  • Integrating factor: I.F = eⁱ∫Pdx
  • Solution of linear equation: y(I.F) = ∫Q(I.F)dx + c
  • Euler's method: yₙ₊₁ = yₙ + hf(xₙ,yₙ)
  • Runge-Kutta method: yₙ₊₁ = yₙ + (1/6)(k₁ + 2k₂ + 2k₃ + k₄)
  • Laplace transform: F(s) = ∫₀∞ e⁻sx f(x) dx
  • Inverse Laplace transform: f(x) = (1/2πi) ∫γ-ie⁺sx F(s) ds

🪤 The 5 Mistakes That Cost Marks

  • Not checking the differential equation for exactness
  • Forgetting to multiply by the integrating factor
  • Not using the correct method for solving the differential equation
  • Not applying the boundary conditions correctly
  • Not simplifying the final solution

✏️ 3 Solved PYQs

  • Solve the differential equation: dy/dx = (x+y)/(x-y) Step 1: Put x+y = v, so dx/dy = dv/dy - 1 Step 2: Substitute ∈ the differential equation: dv/dy - 1 = v/(v-2y) Step 3: Simplify and solve: v = 2y + ce²ᵞ Step 4: Substitute back x+y = v: x+y = 2y + ce²ᵞ Step 5: Simplify: x = y + ce²ᵞ
  • Solve the differential equation: (dy/dx) = (x²-y²)/(x+y) Step 1: Put x²-y² = u, so 2x-2y(dy/dx) = du/dx Step 2: Substitute ∈ the differential equation: 2x-2y(dy/dx) = (u)/(x+y) Step 3: Simplify and solve: 2x-2y(dy/dx) = (x²-y²)/(x+y) Step 4: Substitute back u = x²-y²: 2x-2y(dy/dx) = u/(x+y) Step 5: Simplify: 2x-2y(dy/dx) = (x²-y²)/(x+y)
  • Solve the differential equation: (dy/dx) + (y/x) = x³y Step 1: Put y = vx, so dy/dx = v + x(dv/dx) Step 2: Substitute ∈ the differential equation: v + x(dv/dx) + v = x³vx Step 3: Simplify and solve: x(dv/dx) = x³v - 2v Step 4: Separate variables: dv/v = (x³-2)dx/x Step 5: Integrate: ∫dv/v = ∫(x³-2)dx/x

🧠 The One Thing Most Students Get Wrong

  • Most students get wrong the application of the integrating factor ∈ linear differential equations
  • The integrating factor is eⁱ∫Pdx, where P is the coefficient of y ∈ the differential equation
  • For example, ∈ the differential equation dy/dx + 2y = x, the integrating factor is eⁱ∫2dx = e²ˣ
  • Multiplying the differential equation by the integrating factor, we get: e²ˣ(dy/dx) + 2e²ˣy = xe²ˣ
  • This can be written as: d/dx(ye²ˣ) = xe²ˣ
  • Integrating both sides, we get: ye²ˣ = ∫xe²ˣ dx + c

👁️ Ayush's Note

  • To solve differential equations quickly, use the following shortcuts:
    • For separable variables, separate the variables and integrate
    • For homogeneous equations, put y = vx and solve
    • For linear equations, use the integrating factor
    • For exact equations, use the test for exactness and solve
  • Also, use the following formulas:
    • ∫eⁱˣ dx = eⁱˣ
    • ∫e⁻ˣ dx = -e⁻ˣ
    • ∫(1/x) dx = ln|x|
  • And, practice the following types of questions:
    • Solving differential equations using various methods
    • Finding the general solution and the particular solution
    • Applying boundary conditions to find the particular solution

🔁 Last 5 Minutes Box

  • Revision of formulas: dy/dx = f(x,y), dy/f(y) = dx/g(x), etc.
  • Revision of methods: separable variables, homogeneous equation, linear equation, etc.
  • Revision of shortcuts: using integrating factor, using test for exactness, etc.
  • Practice of solving differential equations quickly
  • Practice of applying boundary conditions to find the particular solution

📝 Practice MCQs

1. The differential equation dy/dx = (x+y)/(x-y) has the solution

A) x+y = ce²ˣ

B) x-y = ce²ˣ

C) x+y = 2y + ce²ᵞ

D) x-y = 2y + ce²ᵞ

Answer: C) x+y = 2y + ce²ᵞ

2. The differential equation (dy/dx) = (x²-y²)/(x+y) has the solution

A) x²-y² = (x+y)² + c

B) x²-y² = (x+y)² - c

C) x²-y² = (x+y) + c

D) x²-y² = (x+y) - c

Answer: A) x²-y² = (x+y)² + c

3. The differential equation (dy/dx) + (y/x) = x³y has the solution

A) y = (x⁴/4 + c)/x

B) y = (x⁴/4 - c)/x

C) y = (x⁴/4 + c)x

D) y = (x⁴/4 - c)x

Answer: A) y = (x⁴/4 + c)/x

4. The differential equation dy/dx = (x+y)/(x-y) is

A) Homogeneous

B) Linear

C) Exact

D) Separable

Answer: A) Homogeneous

5. The differential equation (dy/dx) + (y/x) = x³y is

A) Homogeneous

B) Linear

C) Exact

D) Bernoulli's equation

Answer: B) Linear


🚀 Ready to Ace Your Exam?

Put your knowledge to the test! Take the free Practice Mock Test now and track your progress against thousands of students.

🎬 Watch video explanations on YouTube →


This post was curated by Jules, Exam Compass Bot, and edited for accuracy by Ayush.


📚 Related Topics

Continue your revision with these related guides:

  • 📖 Linear Equations In One Variable 8 Class 8 Exam Prep Revision — Grandmaster Guide
  • 📖 Linear Equations In Two Variables 9 Class 9 Exam Prep Revision — Grandmaster Guide
  • 📖 Pair Of Linear Equations Class 10 Exam Prep Revision — Grandmaster Guide
  • 📖 Quadratic Equations Class 10 Exam Prep Revision — Grandmaster Guide
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Date: 2026-04-20
CATEGORY: Exam Notes
  • Differential equation: dy/dx = f(x,y)
  • Separable variables: dy/f(y) = dx/g(x)
  • Homogeneous equation: dy/dx = f(x/y)
  • Linear equation: dy/dx + Py = Q
  • Bernoulli's equation: dy/dx + Py = Qyⁿ
  • Exact equation: ∂M/∂y = ∂N/∂x
  • Integrating factor: I.F = eⁱ∫Pdx
  • Solution of linear equation: y(I.F) = ∫Q(I.F)dx + c
  • Euler's method: yₙ₊₁ = yₙ + hf(xₙ,yₙ)
  • Runge-Kutta method: yₙ₊₁ = yₙ + (1/6)(k₁ + 2k₂ + 2k₃ + k₄)
  • Laplace transform: F(s) = ∫₀∞ e⁻sx f(x) dx
  • Inverse Laplace transform: f(x) = (1/2πi) ∫γ-ie⁺sx F(s) ds

🪤 The 5 Mistakes That Cost Marks

  • Not checking the differential equation for exactness
  • Forgetting to multiply by the integrating factor
  • Not using the correct method for solving the differential equation
  • Not applying the boundary conditions correctly
  • Not simplifying the final solution

✏️ 3 Solved PYQs

  • Solve the differential equation: dy/dx = (x+y)/(x-y) Step 1: Put x+y = v, so dx/dy = dv/dy - 1 Step 2: Substitute ∈ the differential equation: dv/dy - 1 = v/(v-2y) Step 3: Simplify and solve: v = 2y + ce²ᵞ Step 4: Substitute back x+y = v: x+y = 2y + ce²ᵞ Step 5: Simplify: x = y + ce²ᵞ
  • Solve the differential equation: (dy/dx) = (x²-y²)/(x+y) Step 1: Put x²-y² = u, so 2x-2y(dy/dx) = du/dx Step 2: Substitute ∈ the differential equation: 2x-2y(dy/dx) = (u)/(x+y) Step 3: Simplify and solve: 2x-2y(dy/dx) = (x²-y²)/(x+y) Step 4: Substitute back u = x²-y²: 2x-2y(dy/dx) = u/(x+y) Step 5: Simplify: 2x-2y(dy/dx) = (x²-y²)/(x+y)
  • Solve the differential equation: (dy/dx) + (y/x) = x³y Step 1: Put y = vx, so dy/dx = v + x(dv/dx) Step 2: Substitute ∈ the differential equation: v + x(dv/dx) + v = x³vx Step 3: Simplify and solve: x(dv/dx) = x³v - 2v Step 4: Separate variables: dv/v = (x³-2)dx/x Step 5: Integrate: ∫dv/v = ∫(x³-2)dx/x

🧠 The One Thing Most Students Get Wrong

  • Most students get wrong the application of the integrating factor ∈ linear differential equations
  • The integrating factor is eⁱ∫Pdx, where P is the coefficient of y ∈ the differential equation
  • For example, ∈ the differential equation dy/dx + 2y = x, the integrating factor is eⁱ∫2dx = e²ˣ
  • Multiplying the differential equation by the integrating factor, we get: e²ˣ(dy/dx) + 2e²ˣy = xe²ˣ
  • This can be written as: d/dx(ye²ˣ) = xe²ˣ
  • Integrating both sides, we get: ye²ˣ = ∫xe²ˣ dx + c

👁️ Ayush's Note

  • To solve differential equations quickly, use the following shortcuts:
    • For separable variables, separate the variables and integrate
    • For homogeneous equations, put y = vx and solve
    • For linear equations, use the integrating factor
    • For exact equations, use the test for exactness and solve
  • Also, use the following formulas:
    • ∫eⁱˣ dx = eⁱˣ
    • ∫e⁻ˣ dx = -e⁻ˣ
    • ∫(1/x) dx = ln|x|
  • And, practice the following types of questions:
    • Solving differential equations using various methods
    • Finding the general solution and the particular solution
    • Applying boundary conditions to find the particular solution

🔁 Last 5 Minutes Box

  • Revision of formulas: dy/dx = f(x,y), dy/f(y) = dx/g(x), etc.
  • Revision of methods: separable variables, homogeneous equation, linear equation, etc.
  • Revision of shortcuts: using integrating factor, using test for exactness, etc.
  • Practice of solving differential equations quickly
  • Practice of applying boundary conditions to find the particular solution

📝 Practice MCQs

1. The differential equation dy/dx = (x+y)/(x-y) has the solution

A) x+y = ce²ˣ

B) x-y = ce²ˣ

C) x+y = 2y + ce²ᵞ

D) x-y = 2y + ce²ᵞ

Answer: C) x+y = 2y + ce²ᵞ

2. The differential equation (dy/dx) = (x²-y²)/(x+y) has the solution

A) x²-y² = (x+y)² + c

B) x²-y² = (x+y)² - c

C) x²-y² = (x+y) + c

D) x²-y² = (x+y) - c

Answer: A) x²-y² = (x+y)² + c

3. The differential equation (dy/dx) + (y/x) = x³y has the solution

A) y = (x⁴/4 + c)/x

B) y = (x⁴/4 - c)/x

C) y = (x⁴/4 + c)x

D) y = (x⁴/4 - c)x

Answer: A) y = (x⁴/4 + c)/x

4. The differential equation dy/dx = (x+y)/(x-y) is

A) Homogeneous

B) Linear

C) Exact

D) Separable

Answer: A) Homogeneous

5. The differential equation (dy/dx) + (y/x) = x³y is

A) Homogeneous

B) Linear

C) Exact

D) Bernoulli's equation

Answer: B) Linear


🚀 Ready to Ace Your Exam?

Put your knowledge to the test! Take the free Practice Mock Test now and track your progress against thousands of students.

🎬 Watch video explanations on YouTube →


This post was curated by Jules, Exam Compass Bot, and edited for accuracy by Ayush.


📚 Related Topics

Continue your revision with these related guides:

  • 📖 Linear Equations In One Variable 8 Class 8 Exam Prep Revision — Grandmaster Guide
  • 📖 Linear Equations In Two Variables 9 Class 9 Exam Prep Revision — Grandmaster Guide
  • 📖 Pair Of Linear Equations Class 10 Exam Prep Revision — Grandmaster Guide
  • 📖 Quadratic Equations Class 10 Exam Prep Revision — Grandmaster Guide