Algebraic Expressions 8 Class 8 Mathematics Revision — Grandmaster Guide
Ayush (Founder)
Exam Strategist
- a² - b² = (a + b)(a - b)
- (a + b)² = a² + 2ab + b²
- (a - b)² = a² - 2ab + b²
- (a + b)³ = a³ + 3a²b + 3ab² + b³
- (a - b)³ = a³ - 3a²b + 3ab² - b³
- a³ + b³ = (a + b)(a² - ab + b²)
- a³ - b³ = (a - b)(a² + ab + b²)
- a² + b² = (a + b)² - 2ab
- a² - b² = (a + b)(a - b)
- (x + a)(x + b) = x² + (a + b)x + ab
- (x - a)(x - b) = x² - (a + b)x + ab
- (x + a)(x - b) = x² + (a - b)x - ab
- (x - a)(x + b) = x² + (b - a)x - ab
🪤 The 5 Mistakes That Cost Marks
- Not simplifying expressions before solving
- Not factoring out common terms
- Not using the correct formula for expansion
- Not combining like terms
- Not checking the answer by plugging it back into the original equation
✏️ 3 Solved PYQs
- Solve: (2x + 5)(3x - 2) Step 1: Use the formula (a + b)(c + d) = ac + ad + bc + bd Step 2: Apply the formula: (2x + 5)(3x - 2) = 2x(3x) + 2x(-2) + 5(3x) + 5(-2) Step 3: Simplify: 6x² - 4x + 15x - 10 Step 4: Combine like terms: 6x² + 11x - 10
- Solve: (x + 2)² Step 1: Use the formula (a + b)² = a² + 2ab + b² Step 2: Apply the formula: (x + 2)² = x² + 2(x)(2) + 2² Step 3: Simplify: x² + 4x + 4
- Solve: x² - 16 Step 1: Use the formula a² - b² = (a + b)(a - b) Step 2: Apply the formula: x² - 16 = (x + 4)(x - 4)
🧠 The One Thing Most Students Get Wrong
- Most students get wrong the expansion of (a + b)(a - b) as a² + b² instead of a² - b²
- This mistake can be avoided by remembering the formula a² - b² = (a + b)(a - b)
👁️ Ayush's Note
- Always remember to factor out common terms from expressions
- Use the formula (a + b)(a - b) = a² - b² to simplify expressions
- Always check the answer by plugging it back into the original equation
🔁 Last 5 Minutes Box
- Last minute revision of formulas: a² - b² = (a + b)(a - b), (a + b)² = a² + 2ab + b²
- Quick practice of simple questions: (x + 2)(x - 2), x² - 4
- Revision of common mistakes: not simplifying expressions, not factoring out common terms
📝 Practice MCQs
1. What is the value of (2x + 3)(2x - 3)
A) 4x² - 9
B) 4x² + 9
C) 4x² - 6x - 9
D) 4x² + 6x + 9
Answer: A) 4x² - 9. Explanation: Using the formula a² - b² = (a + b)(a - b), we get (2x + 3)(2x - 3) = (2x)² - 3² = 4x² - 9
2. What is the value of (x + 2)²
A) x² + 4x + 4
B) x² - 4x + 4
C) x² + 2x + 4
D) x² - 2x - 4
Answer: A) x² + 4x + 4. Explanation: Using the formula (a + b)² = a² + 2ab + b², we get (x + 2)² = x² + 2(x)(2) + 2² = x² + 4x + 4
3. What is the value of x² - 16
A) (x + 4)(x - 4)
B) (x + 4)(x + 4)
C) (x - 4)(x - 4)
D) (x + 2)(x - 2)
Answer: A) (x + 4)(x - 4). Explanation: Using the formula a² - b² = (a + b)(a - b), we get x² - 16 = (x + 4)(x - 4)
4. What is the value of (3x + 2)(2x - 1)
A) 6x² + 5x - 2
B) 6x² - 5x - 2
C) 6x² + x - 2
D) 6x² - x - 2
Answer: A) 6x² + 5x - 2. Explanation: Using the formula (a + b)(c + d) = ac + ad + bc + bd, we get (3x + 2)(2x - 1) = 3x(2x) + 3x(-1) + 2(2x) + 2(-1) = 6x² - 3x + 4x - 2 = 6x² + x - 2
5. What is the value of (x - 3)²
A) x² - 6x + 9
B) x² + 6x + 9
C) x² - 3x + 9
D) x² + 3x - 9
Answer: A) x² - 6x + 9. Explanation: Using the formula (a - b)² = a² - 2ab + b², we get (x - 3)² = x² - 2(x)(3) + 3² = x² - 6x + 9
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📚 Academic References
Content verified against peer-reviewed research:
- A framework for entrepreneurial learning in higher education — Academic Journal (2016) 🔓 — DOI ↗
- MIRA: An LLM-Driven Dual-Loop Architecture for Metacognitive Rewa... — Systems (2025) 🔓 — DOI ↗
- Mathematical methods and human thought in the age of AI — ArXiv.org (2026) 🔓 — DOI ↗
🔓 = Open Access article
This post was curated by Jules, Exam Compass Bot, and edited for accuracy by Ayush.
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